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* Assuming it's liquid * Molecular weight : 28.0134 g/mol * Liquid density (1.013 bar at boiling point) : 808.607 kg/m3=808.607g/L 10.5L = 8490.3735 g divide by 28.0134 = 303.0825 mol
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How many moles of N2 are produced by the decomposition of 1.20 mol of NaN3?
The number of atoms is 45,166.10e23.
Can be measured only by its effects on matter?
Give the number of moles of N2 in 70.05 g of N2, (molar mass of N2 = 28.02 g/mol)
How do you get the number of moles in 28grams per mole of N2?
Use the dimensional analysis to get your answer
What mass of NH3 is produced when 1.20 mol of N2 react completely in the following equation N2 plus 3H2 2NH3?
N2 + 3H2 ==> 2NH3moles N2 = 1.20 molesmoles NH3 formed = 1.20 moles N2 x 2 moles NH3/1 moles N2 = 2.40 moles NH3mass NH3 = 2.40 moles x 17 g/mole = 40.8 g NH3
If 5.0 moles of NH3 are produce how many moles of N2 must have been used?
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
How many moles of N2 are produced by the decomposition of 1.20 mol of NaN3?
The number of atoms is 45,166.10e23.
How do you find the number of moles of nitrogen gas in 3.2L?
1 mole N2 = 22.4L 3.2L N2 x 1mol N2/22.4L = 0.14 mole N2
How many moles of H2are needed to react with 0.90moles N2?
I assume you mean this reaction. N2 + 3H2 --> 2NH3 0.90 moles N2 (3 moles H2/1 mole N2) = 2.7 moles hydrogen gas needed =====================
Can be measured only by its effects on matter?
Give the number of moles of N2 in 70.05 g of N2, (molar mass of N2 = 28.02 g/mol)
How do you get the number of moles in 28grams per mole of N2?
Use the dimensional analysis to get your answer
What mass of NH3 is produced when 1.20 mol of N2 react completely in the following equation N2 plus 3H2 2NH3?
N2 + 3H2 ==> 2NH3moles N2 = 1.20 molesmoles NH3 formed = 1.20 moles N2 x 2 moles NH3/1 moles N2 = 2.40 moles NH3mass NH3 = 2.40 moles x 17 g/mole = 40.8 g NH3
If 5.0 moles of NH3 are produce how many moles of N2 must have been used?
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
How many moles of N2 reacted if 0.40 mole NH3 is produced?
2 x 0.60 = 1.2 the reaction is N2 + 3H2 -> 2NH3 (1 mole of nitrogen N2 give 2 moles of NH3)
How do you find if you have 14.5 moles of N2 how many moles of H2 are theoretically needed to produce 22.5 moles of NH3 according to the reaction N2 plus 3H2 2NH3?
N2 + 3H2 -> 2NH3 If you have moles produced you can do it this way. 22.5 moles NH3 (3 moles H2/2 moles NH3) = 33.8 moles H2 needed -----------------------------------
Do chemical reactions contain the same number of moles as reaction proceeds?
Not necessarily. Some reactions do have the same number of moles, and some do not.Examples: NaCl + AgNO3 ==> NaNO3 + AgCl same # of moles N2 + 3H2 ==> 2NH3 different # of moles
How many moles of N2 are in 50g of it?
50g/28g= 1.7857 moles
When 3 moles of N2 reacts with 2 moles of H2 the number of produced moles of ammonia equal?
The reaction between nitrogen and hydrogen to form ammonia is: N2 + 3 H2 → 2 NH3 The above is the reaction for the Haber process in the industrial synthesis of ammonia. For a given proportion of 3 N2 to 2 H2 (or in ratio terms equivalent to 4.5 N2 to 3 H2), we see that H2 is the limiting reactant. Thus according to the stoichiometry of the reaction, 2 moles of H2 will form 1.33 moles of NH3.
