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How do you calculate the speed of an electron using the de Broglie wavelength?
Wiki User
∙ 7y ago
To find this answer you will have to go through a series of formulas. The first formula you will need to use is the kinetic energy formula (K.E.=1/2mv^2). The mass of an electron is found to be 9.11 x 10^-31. You then divide the mass by two (or multiply by 0.5) and get 4.555 x 10^-31, you will then have to multiply it by your velocity squared, and get your energy in joules. With that energy, you divide by planks constant (6.6 x 10^-34) which eaves you with your frequency. With that very frequency you get the speed of light in air (3 x 10^8) and divide by your frequency which will give you the wavelength needed in meters
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoUse the de Broglie equation. Max Planck said that the energy was a constant (which we now call Planck's constant, for obvious reasons) multiplied by the wavelength. Albert Einstein said that energy was mass multiplied by the speed of light in a vacuum squared. Louis de Broglie said energy was energy, and therefore the wavelength of a mass is the mass multiplied by the speed of light in a vacuum squared, divided by Planck's constant.
Wiki User
∙ 7y agoSpeed of electron = [ planck's constant ] / [ mass x wavelength ]
or v= h/ [m x lambda ]
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If proton and an electron have the same speed which has the longer de Broglie wavelength?
It is electron since wavelength = h/(mv), and since proton's mass > electron's mass, electron's wavelength is longer.
What is the speed of the electron with a de Broglie wavelength of 235nm?
The DeBroglie wavelength of an electron with 1 eV KE and rest mass energy 0.511 MeV is 1.23 nm. This is around a thousand times smaller than a 1 eV photon. To find the DeBroglie wavelength of an electron, simply divide Planck's constant by the momentum of the electron.
How do you calculate the frequency of light emitted in chemicals?
There are several ways to calculate the frequency of light emitted or absorbed by different chemicals, and they depend on what you already know. For example, if you know the energy of the particle, then you can calculate frequency from E = planck's constant x frequency and solve for frequency. If you happen to know the wavelength, then you can use C = wavelength x frequency and solve for frequency (where C = speed of light).
Because c the speed of electromagnetic radiation is a constant the wavelength of the radiation is....?
The wavelength is inversely proportional to its frequency. That is, as the frequency increases, the wavelength decreases and vice versa.
Velocity of a wave increases and the wavelength stays the same. What will the result be when this happens?
Assuming an electromechanical wave not much. The speed of the wave depends on the medium that the wave is passing through. In a vacuum it is the speed of light, through something else a lesser speed. The wavelength stays the same and the frequency stays the same.
If proton and an electron have the same speed which has the longer de Broglie wavelength?
It is electron since wavelength = h/(mv), and since proton's mass > electron's mass, electron's wavelength is longer.
What is de broglie's wavelength of electron in meters travelling at half a speed of light?
4.2*10-11
What is de-Broglie wavelength of an atom at absolute temperature T K?
de Broglie wavelength depends only on the mass and speed of the particle and not on the temperature
Why is de broglie wavelength associated with macroscopic objects is not observed in daily life?
Because such a wavelength is way too small to be significant. The de Broglie wavelength is inversely proportional to an object's momentum (mass x speed).
What is the characteristic wavelength of the electron when an electron is accelerated through a particular potential field if it attains a speed of 9.38x10 to the power of 6 ms?
A characteristic wavelength of an electron can be known as the DeBroglie Wavelength. It is a formula in physics which relays energy and momentum.
An electron starting from rest accelerates through a potential difference of 388 V What is the final de Broglie wavelength of the electron assuming that its final speed is much less than the spee?
An electron, starting from rest, accelerates through a potential difference of 417 V.
Who stated that matter behaves as both waves and particles?
Louis de Broglie
How to calculate the wavelength?
This question is from Bohr's atomic model. The total length of the orbit is an integral multiple of the wavelength of an electron. The relation given by 2(pi)(radius)=n(wavelength), where n is the principal quantum number. Proof of this came later from De-Broglie's hypothesis, (wavelength)=h/(linear momentum) It is- (wavelength)=h/mv .....I From Bohr's model (Quantization of angular momentum), mvr=nh/2(pi) So, 2(pi)r=n(h/mv) From I, 2(pi)r=n(wavelength)
How do you calculate the wavelength?
Wavelength = (wave speed) divided by (frequency)
How do you calculate light wavelength to frequency?
To find (wavelength): Divide (speed) by (frequency). To find (frequency): Divide (speed) by (wavelength).
How do you calculate the wavelength of frequency?
Wavelength = (speed of the wave) divided by (frequency)
What is the De Broglie wavelength of an electron that strikes the back of the face of a TV screen at 19 the speed of light?
Assuming you mean that the velocity is 1/9th the speed of light then you need to use the de Broglie equation for the wavelength of a particle, which says that the wavelength is equal to Planck's constant divided by the momentum. Thus, λ = h / p = h / (m*v) = h/(m*1/9*c) = 9*h/(m*c) where λ=wavelength, h=Planck's constant, p=momentum, m=mass of the electron, v=velocity, and c=speed of light this gives λ = 9 * 6.626*10^-34 / (9.109*10^-31 * 3.00*10^8) = 2.18*10^-11 meters
