Assuming that at one time a positive potential exists on a anode then assign a [+] to that point follow this procedure for all diodes and resistors. You can calculate Boltzmann impedance of a diode but industry wise a .6v to.8v is standard practice for a diode drop since it follow an exponential curve. .6 volts is for low current and .8volts is for more current
The voltage across the resistor is whatever voltage is applied. The only maximum here would be a voltage that would damage the resistor. If you think this might happen, you'll have to look up such a voltage from the data sheets.
To calculate the currents ir1 and ir2 in a parallel circuit of two resistors r1 and r2, consider the voltage across them. By Kirchoff's voltage law, the voltage across each resistor will be the same, so simply use Ohm's law to divide voltage by each resistor to get each resistor's current. ir1 = v / r1 ir2 = v / r2 If you don't know voltage, but you do know total current, then determine the total resistance as RT = R1R2/(R1+R2), calculate voltage as ITRT and proceed from there.
Voltage x current. In a resistor for example it is the voltage drop across it that is relevant, it may be part of a circuit.
To reduce DC voltage with a zener diode you place a resistor in series with the zener and setup for the reverse bias condition. You pick the resistor to bias the zener at the desired reverse current. You also have to consider the load across the resistor, across the zener, and across the target load. Often, this configuration is used to establish a reference voltage for something else, such as an op-amp controlled emitter-follower, but it is possible to use just the resistor and zener if you consider all the factors.
A voltmeter can be connected in parallel with a resistor to show the voltage across the resistor.
A: by using thevenin theorem
No. If a voltage is applied across a resistor, a current flows through it.
The voltage across the resistor is whatever voltage is applied. The only maximum here would be a voltage that would damage the resistor. If you think this might happen, you'll have to look up such a voltage from the data sheets.
Volt across a resistor = resistance x current through the resistor.
To calculate the currents ir1 and ir2 in a parallel circuit of two resistors r1 and r2, consider the voltage across them. By Kirchoff's voltage law, the voltage across each resistor will be the same, so simply use Ohm's law to divide voltage by each resistor to get each resistor's current. ir1 = v / r1 ir2 = v / r2 If you don't know voltage, but you do know total current, then determine the total resistance as RT = R1R2/(R1+R2), calculate voltage as ITRT and proceed from there.
It doesn't. In a series circuit, the largest voltage drop occurs across the largest resistor; the smallest voltage drop occurs across the smallest resistor.
The protecting resistor is put in series with the LED so that you have a voltage divider - the supply voltage is split across the LED ( max 0.6v) and the remainder across the protecting resistor. So if your supply is 6volts, 5.4v will be across the resistor,
Normally through the resistor's internal construction. It flows through any part of the resistor that has low resistance- be it anywere. And then there's this. It might be that one should consider that current flows through a resistor and voltage is dropped across a resistor. Perhaps this is where the question began. The former is fairly straight forward. The latter can be vexing. Voltage is said to be dropped across a resistor when current is flowing through it. The voltage drop may be also considered as the voltage measureable across that resistor or the voltage "felt" by that resistor. It's as if that resistor was in a circuit by itself and hooked up to a battery of that equivalent voltage.
The correct question is what is the voltage drop across a resistor or the current flowing through the resistor using Ohm's Law where Voltage = Current x Resistance
p=I*I*R ,P=V*V/R;where I is the current passing through the resistor, and V is the voltage across resistor, and R is the Resistance of the resistor,
Voltage x current. In a resistor for example it is the voltage drop across it that is relevant, it may be part of a circuit.
Current flows in loops, voltage drops across elements. With relation to current, what flows in, must flow out, so no, current is not dropped across a resistor, it flows through a resistor and voltage is dropped across the resistor.