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Is an OSHA Recordable case a legal obligation and requirement?
You are legally required to record and OSHA recordable case.
If a wave has a wavelength of 9 meters and a period of 0.006 what is the velocity of the wave?
The speed of the wave is equal to wavelength x frequency. You can calculate the frequency, in this case, as 1 / period.
Is a heart attack a OSHA recordable?
A heart attack may be an OSHA Recordable event, but it may not, depending on the circumstances. It it is thought to be the result of one's work assignment, it would be Recordable. But events like heart attacks can happen at work without being work-related, so some (many) are not OSHA recordable. A knowledgeable person would have to determine that on a case by case basis.
Calculate the energy per photon of radio waves of frequency 107.3 MHz?
E = hf The energy per photon is equal to Planck's constant times the frequency, in this case 6.62606957×10−34 x 107.3x106
What is the lowest frequency that can be generated using mode 1 if the crystal frequency is 11.0592 MHz Show your calculations?
To calculate the lowest frequency that can be generated using mode 1, we need to divide the crystal frequency by two. So, the lowest frequency that can be generated in this case would be 11.0592 MHz divided by 2, which is equal to 5.5296 MHz.
If a wave have long wavelength it has a what frequency?
In that case, it will have a low frequency.
How do you calculate average speed in case of stop overs?
ave speed does not care if you have stopovers or not. ave speed = total distance / total time
How do you find the wave speed with the wavelength and amplitude?
Not enough information. You can use the equation speed = frequency x wavelength, but in this case, you don't have enough data to calculate the speed.
How do you calculate an image frequency?
Let's take an example. Suppose that the intermediate frequency is 10,7 MHz (FM). The local oscillator works on 110,7 MHz. First case: You receive a signal of 100 MHz, the mixer will generate a frequency of 110,7 + 100 = 210,7 MHz, which will be rejected by the band-pass filter. The difference of the two frequencies is 110,7 - 100 = 10,7 MHz (desired one). Second case: You receive a signal of 121,4 MHz. The sum of that frequency and the local oscillator is 232,1 MHz, which will be rejected. The difference is 121,4 - 110,7 = 10,7 MHz. So the image frequency in that case is going to be 121,4 MHz.
89kHz sinusoidal signal is modulated using an amplitude modulator and a frequency modulator calculate the bandwdith requirement for both modulation schemes?
You can't do this unless you know more detail on the frequency modulator, like its modulation index, for example or the frequency deviation. For the amplitude modulator, it is easy. Bandwidth is twice the signal frequency so in this case the bandwidth is 178kHz for AM.
When wavelength decreases does the frequency increase or decrease?
The wavelength is inverse to the frequency, meaning the frequency in this case will increase.
Doppler effect with two people moving to each other?
In this case, the frequency of a wave emitted by one person would increase (be perceived as having a higher frequency) by the other.In this case, the frequency of a wave emitted by one person would increase (be perceived as having a higher frequency) by the other.In this case, the frequency of a wave emitted by one person would increase (be perceived as having a higher frequency) by the other.In this case, the frequency of a wave emitted by one person would increase (be perceived as having a higher frequency) by the other.
