This is for pearl i dont know if it is the same.
Talk to the owner of the trophy garden Mr Backlot and say yes to everything he says he with tell you there isa porygon in the garden use the pokeradar to find it
Then talk to oak in eterna and he will give you an up Grade give it to porygon and trade it and it will evolve into porygon 2
Then go to rout 225 and look for the dubious disc and give it to porygon 2 and trade it and it will evolve into Porygon Z
You trade from Pokemon FireRed/LeafGreen
end ofiron island
veilstone city, in a house right above the Pokemon center
You have to beat the Elite 4 and have seen every single Pokemon.
griseous orb
You'll need to trade in 9,999 coins in the Game Corner for Porygon.
i think the only way you can get that is by an action replay
i always asked myself how to obtained porigon 2 thanks. and actually yes there is one if you have 2 games. place the Pokemon on the gts and immediately with the other game trade it for any Pokemon you want to. if you do not have any game other than platinum there is also a way. deposit a Pokemon like magmar holdig the magmazier or jou know and ask for the Pokemon and i don't know if its porigon z or porigon but i can check. or did you mean just to SEE not to CATCH? here`s the answer. in the victory road i don't remember who had it. if you havent got there or you used action replay to walk throught walls just entering is necesary. but if you used catch trainer Pokemon i`m very sorry. or obtaining it with only one ds in all of the ds in the world by cheating.
Have it hold upgrade trade it to a friend then take it back to receive porygon2.
you cannot get any other rod then the super rod (you get the super rod after you beat the game and talk to looker a police officer from the sinnoh region in Pokemon platiunum)
All the Pokemon from the Diamond and Pearl Sinnoh Dex, plus 60 others. These include, Ralts (and evolutions), Houndour (and evolutions), and Giratina. if you are not sure like i am \ was then check out serabii.net for more info
No, it's impossible.