Java has auto-boxing introduced in Java 5 and converts ints to Integer objects as needed.
Or you can explictly call Integer.valueOf(int) or new Integer(int) to return an Integer object with the value of the primitive int argument.
Example:
int i = 14; // i = 14
Integer a = Integer.valueOf(i); // a = 14Integer b = new Integer(i); // b = 14
or simply
Integer c = i;
Only Objects can be used as generic arguments. Primitives Data Types (int, long, char ...) are not objects. But you can use Integer, an Object that wrap the data type int instead.
String itself is an object dude... If you want an object out of a string then you can do this. Object obj = (Object) str; //str is the String you want to convert to object.
No, it is not strictly object oriented. Java still maintains the concept of primitive data types, such as char, int, long, float, double, boolean. And as such, these are not objects. In a true object oriented language, everything would be represented as an object, including operators. sory but wappers implement this concept n everything in java done by a class n a object it strickly follow the 3 rules of oops for detail refers java2 complete reference chapter2
Java is not a true object-oriented language.One of the requirements for such a title is that everything must be an object. Java contains non-object primitive values (such as int, float, boolean, etc.).
All of the Java number classes have a parse[type] method, like parseInt() in Integer or parseDouble() in Double that convert Strings to primitive numbers. String s = getInput(); int var = Integer.parseInt(s);
One can convert a string variable to an int variable in Java using the parse integer command. The syntax is int foo = Integer.parseInt("1234"). This line will convert the string in the parenthesis into an integer.
To convert string to int in Java, the easiest way is to simply use the method Integer.parseInt(). For more information how to do this, refer to the integer class documents.
java is not purely oops because of primitive types in java like int and float double
long a; int b; b = a.intValue(); //IMPORTANT NOTE IF THE LONG IS SO LARGE THAT IT CANT BE A INT THEN YOU WILL GET A OVERFLOW ERROR
Assuming - char mychar ; and int myint have been properly declared, myint = (int) mychar; // converts This is a feature of Java= to change types, put the type you want to convert into in parenthes before the variable that stores the converted value. ^Will convert your char into an int, but it will be the ascii value. For example, mychar = 3; myint = (int) mychar; //returns 51 To make an accurate one that will not return an error, you can use a try-catch statement Example char mychar = '3'; try { int myint = (int) mychar; }catch(NumberFormatException e) { //Do whatever you want with it! }
In java, the String object has a compareTo() method. The method returns an int. If the int is less than zero, the first string is less than the second. If the int is greater, the first is greater than the second. If the int is zero, the two strings are equal.
initialize simple types: int i = 0; initialize objects: Object o = null; (in java)
Java is not a completely object oriented language, because not all values in Java are Objects. For example, the basic numeric types such as int, long, double, etc., are not objects and need to be "boxed" into objects in order to pass them as Object parameters or call methods on them.
Within Java, an integer is an Object, which is converse to the "int", which is a primitive. In reality, this means that for an integer, a method can be called upon it, whereas with a primitive, this is not the case.
int is integer which means datatype
Only Objects can be used as generic arguments. Primitives Data Types (int, long, char ...) are not objects. But you can use Integer, an Object that wrap the data type int instead.
The same way you would in a regular java program. int i = 10; String s = i + ""; after the above line of code the variable s will have "10" as a string value...