Decibels (db) is 3 times the log based 2 of the difference in power.
To convert from db to power, divide by 3 and compute the inverse log based 2. For example, +6db is 26/3 or 22 or 4 times the power, and -9db is 2-9/3 or 2-3 or one eighth the power.
If you are attempting to compute voltage, remember that db is power difference, so you need to take the square root of the difference, because power is voltage times current, and current is voltage divided by resistance, so power is voltage squared divided by resistance.
The 'm' in dBm means the power is referenced to 1mW. So, the power in dBm equals 10 times the log of the power in mW, or P(dBm) = 10*log(P(mW)/1mW). For example, 1W = 1000mW, so 10*log(1000/1) = 30dBm.
Here you find the formula to convert voltage levels to decibels. Scroll down to related links and look at "How to calculate dB?"
In power wattage increases by two times for every three DBs of increase. A starting point is needed to do this calculation. The equation you're looking for is 10*log |P| = P in dB for example, 0 dB = 1 watt 10 dB = 10 watts for 13.936dB, 10^1.3936 = 24.75 watts.
Decibels (db) is relative power, log base 2, times 3. Increasing power from 200 watts to 400 watts is doubling power, so the decibel change is +3 db.800 watts would be +6 db, 1600 watts would be +9 db, 100 watts would be -3 db, 50 watts would be -6 db, and so on.
If you want to work in watts, convert 25dB to a scalling factor: 3dB = 2 x input 10dB = 10 x input 20dB = 100 x input ...25dB = 10 ^ (25/10) = 316.2 x input So the output is 15 micro Watts x 316.2 = (4700)/(10^6) = 4.7 milli watts If you want to work in dB, then convert 15 micro watts to dB: 10 * log |P| = dB = 10*log |15 x 10^6| = -48.2dB ***When you have very small (ie negative) dB, it is often referred to in dBm, or 1/1000 of dB ( 30 dBm = 0 dB) so the output is -18.2dBm + 25 = 6.8dBm, or -23.2dB
the first convert the power in dBm to MW, the define of dBm=10 log (P MW) -10 log ( 1mw). example: let P=-2 dBm convert this to dB? answer: Pmw= inv log(-2/10)=0.630mw*1000 micw/mw=630 microw 10log(630)=28dB
How do I convert a .db file?
using bode-m plots , one can tranfer dB magnitude to gain and gain to frequency
The 'm' in dBm means the power is referenced to 1mW. So, the power in dBm equals 10 times the log of the power in mW, or P(dBm) = 10*log(P(mW)/1mW). For example, 1W = 1000mW, so 10*log(1000/1) = 30dBm.
Here you find the formula to convert voltage levels to decibels. Scroll down to related links and look at "How to calculate dB?"
Given P = 100 watts. Reference sound intensity Po = 10^−12 W. Reference sound intensity level LPo = 0 dB. Get power level LP in dB when entering sound power P in watts. Power level LP = 10×log (P / Po) dB = 10×log (100 / 10^−12) = 140 decibels (dB).
In power wattage increases by two times for every three DBs of increase. A starting point is needed to do this calculation. The equation you're looking for is 10*log |P| = P in dB for example, 0 dB = 1 watt 10 dB = 10 watts for 13.936dB, 10^1.3936 = 24.75 watts.
You cannot convert DBi to DB because they are not related. DBi is only for decibels in an isotropic radiator, while DB is only for decibels in a dipole antenna.
Decibels (db) is relative power, log base 2, times 3. Increasing power from 200 watts to 400 watts is doubling power, so the decibel change is +3 db.800 watts would be +6 db, 1600 watts would be +9 db, 100 watts would be -3 db, 50 watts would be -6 db, and so on.
If I understand the question, it isn't possible to convert dB (a unit of sound energy) to litres (a unit of volume).
dB = 10 log(power-2/power-1) = 10 log(80) = 19.03 dB
Increase = 10 log(B/A) dB = 10 log (3000/1) = 10 ( 3.47712) = 34.8 dB (rounded)