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Answered 2013-08-27 01:43:11

You point at the array the same way you would with an array of any pointer type, by using an additional level of indirection than is employed by the pointers in the array itself. In this case, the array contains pointer-to-function data types (with one level of indirection), thus you must use a pointer-to-pointer-to-function data type (with two levels of indirection) in order to point at the array itself.

Had the array contained pointer-to-pointer-to-function data types (where each pointer points to a separate array of pointer-to-function data types), then you'd use three levels of indirection, and so on.

You increase the level of indirection by placing an additional asterisk before the pointer's name when you declare the pointer. That is, one asterisk per level.

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An array of pointers is that for eg if we have array of 10 int pointers ie int *a[10] then each element that which is stored in array are pointed by pointers. here we will have ten pointers. In pointer to an array for eg int(*a)[10] here all the elements that is all the ten elements are pointed by a single pointer.


There is no such thing as an "array to pointer." What you might be asking is "array of pointers." An array of pointers is just that, an array in which the variables are pointers. In C this would be an array of pointer variables that are each 4 bytes in size. It is declared like this: int *pointers[3]; A pointer to an array is a pointer that points to the whole array. For example, in C if you have int numbers[5][10]; int (*pointerToArray)[10] = numbers + 2; pointerToArray points to the third element of numbers, which is itself an array.


Yes. For example, argv parameter of function mainis a pointer to an array of pointers to characters.


An array of pointers is exactly what is says on the tin - an array which contains pointers to memory addresses.If you were to create an array of ten integers like this:int array[10];This would create an array which you could directly access from the stack (memory allocated to the program by the Operating System).However, if you wanted to create an array of pointers to integers, allowing for a more efficient use of memory, you could do this:int *array = new int[10];This dynamically allocates an array of 10 pointers to integers.Comment:This example is hardly an efficient use of memory. Not only are you declaring 10 integers, you are declaring a pointer, which uses slightly more memory than would otherwise be required by the first example. An array of pointers is more useful when the memory they point to is non-contiguous and the number of elements is dynamic rather than static. Even dynamic multi-dimensional arrays can be allocated in contiguous space and simple pointer arithmetic can be used to access any element, thus only one pointer is required for the entire array rather than separate arrays of pointers and pointer-to-pointer arrays for each dimension. While pointer arrays can often improve performance, it is always at the expense of memory consumption.


When a array is passed to a function, the array is internally changed to a 'pointer'. And pointers are always passed by reference. Hence the answer to the question.


Arrays are implemented as pointers in c.


Please ask just one question at a time!Question 1:How do you declare an array of three pointers to chars?How do you declare an array of three char pointers?Note: both of these questions are merely alternative wordings for the same question.Answer 1:char * a[3];Question 2:How do you declare a pointer to an array of three chars?Answer 2:char a[3]; // an array of three charschar * p = a; // a pointer to an array of three charsQuestion 3:How do you declare a pointer to a function which receives an int pointer?Answer 3:#include // some functions we can point at:void func_1(int * p){}void func_2(int * p){}// note: all functions we wish to point at with the same// pointer must have the same signature.int main(){int* p = NULL; // instantiate an int pointervoid (*pFunc) (int*); // declare a function pointerpFunc = func_1; // point to func_1pFunc(p); // call func_1 via function pointerpFunc = func_2; // point to func_2pFunc(p); // call func_2 via function pointerreturn(0);}Note that the brackets in the function pointer declaration are required. If you omit them, you will end up with a standard function declaration that returns a pointer to void, resulting in a compiler error.


A pointer into an array of elements of type E is a pointer to a single element of type E:typedef ..... E;E array[123];E* const pointer = &array[18]; // points to the 19th element inside 'array'An array of pointers is an array whose elements are pointers:typedef .... E;E* array[123];E** const pointer = &array[18]; // points to the 19th pointer within 'array'Referencing the name of the array variable without use of the index operator itself is a constant pointer to its first element. Therefore, the following if-clause is always true:typedef .... E;E array[123];if (array &array[N]) { // ALWAYS true ...}


Because of pointers and that all arrays are really pointers. A pointer something like *pointer can also be written as pointer[0] and *(pointer + 1) can also be written as pointer[1]


array and pointer both are derived datatypes..


If the array is static you can simply point at the first element. For dynamic arrays you can allocate a contiguous block to a single pointer which can then be subdivided using a one-dimensional array of pointer to pointers, each of which points to a one-dimensional array of pointers, each of which points to a separate object within the array. For extremely large arrays, however, it is better to split the elements into separate one-dimensional arrays, by creating a one-dimensional array of pointer to pointers first, then allocating each of those pointers to a separate one-dimensional array of pointers, each of which points to a separate one-dimensional array of objects. Either way, you must destroy all the individual arrays in the reverse order of creation.


char* a[3]; char* b[3]; char[3] *c; void(*d)(int*); Note that these are definitions. To make these declarations only, use the keyword 'extern'.


Function Pointers are basically used when we want to select a function which is to be used dynamically at run time.AnswerFunction pointers are the only way for "Interept programming". In UNIX all the Interepts are called using function pointers. This is mainly used in system programming. Answerits nothing but a pointer to function. which is similar to ptr to a variable, if we are saying ptr to a variable then it will hold address of the variable like that fn. ptr will have the address of the function.. one of the major application of the function pointer is call back function.. i.e callback.AnswerPointers to functions/methods/subroutines aka 'Delegates' are frequently used in .NET programming especially in EventHandling, MemberInvoking A function pointer is used to pass a function as an argument to another function, or to store a function as a data item, for example a list of functions can be implemented as an array of pointers to functions. Function pointers are used to store interrupt handlers in tables.


By returning a pointer to the first element of the array.


function pointer is a variable that hold the address of any function which declared in the program but function pointer is the array of the function that accept the run time size of the function.


There is a difference: a pointer is a number that literally points to a place in memory. Arrays are groupings of a type. There is a close relationship between pointers and arrays, however: every expression with arrays (example: array[i]) can be expressed with pointers (example: *(array + i)), because for the computer, an array is just a list of pointers to the type of the array.


A pointer is normally considered an atomic data type. Therefore, a pointer cannot "be indexed like an array" in that it is not possible to access portions of a pointer through an index. However, a pointer can point to data which can be accessed through pointer operations as well as through index operations. Further, multiple pointers can be arranged in an array of pointers, and each individual pointer within that array of pointers can be reached through its array index. Example 1: an array of pointers const char* const array_of_pointers[] = { "Hello, World", "Hello, Venus", "Hello, Mars" }; In this example, each of array_of_pointers[0], array_of_pointers[1] or array_of_pointers[2] evaluates to one pointer, selected with the array index 0..2. Example 2: access to data through pointer using an array-style index void example(char* const text) { *text = 'a'; // set first character pointed to to 'a' *(text+1) = 'b'; // second char becomes 'b' // the following are equivalent to the above, but use index notation: text[0] = 'a'; text[1] = 'b'; } Key to example 2 is the declaration of the pointer as a constant pointer.


a pointer is a variable that contains memory location of another variable.the value u assign to the pointers are memory address of other variable.


A hard question to answer. If you do not understand the concept of array and the concept of pointer nothing I can tell you will be meaningful. Learn about arrays and pointers and the answer will be self evident.


The declaration of an array of 3 int pointers will be: int *p[3]; The declaration of a function that receive an array of int pointers will be: int my_func(int **p); or int my_func(int *p[]); and you can pass it to other function simply by passing p.


There are no array operations in C. Arrays implicitly convert to pointers, thus any operation you might attempt upon an array you would actually perform on a pointer.


A pointer is a variable like any other. As such, it has memory allocated to it. It is similar to an int in that they both store a value in their memory location. However, whereas an int value is interpreted as a whole number, a pointer's value is interpreted as a memory address. The pointer is said to "point to" the memory address it contains. The type of the pointer determines the type of the variable stored at that memory address. the following is a declaration of a pointer to an integer initialised with the value zero: int * p = new int(0); A pointer to a pointer is no different to an ordinary pointer, except the memory address it points to is that of another pointer. The following is an example of a pointer that points to the pointer we've just declared. int ** pp = p; Pointer-to-pointer variables are typically used whenever you need to pass a pointer by reference. All pointers are passed by value, so the memory address they contain is passed, not the pointer variable itself. To pass the pointer itself, you must pass a pointer to the pointer, which passes the memory address of the pointer. This then makes it possible to change the memory address stored in that pointer. Pointer-to-pointer variables are also used when declaring dynamic, multi-dimensional arrays. For instance, a 2-dimensional array requires a pointer-to-pointer to reference the array itself. This pointer points to a 1-dimensional array of pointers, each of which points to a 1-dimensional array of the actual variables in the array. Unlike a static multi-dimensional array, where the entire array occupies contiguous memory, a dynamic multi-dimensional array may not reside in contiguous memory. Pointer-to-pointer can be extended further to accommodate 3-dimensional arrays, and above. A 3D array requires a pointer-to-pointer-to-pointer, which points to a 1-dimensional array of pointer-to-pointer, each of which references a 2D array, as previously outlined.


Passing array elements to a function is achieved by passing the individual elements by reference or by value, just as you would any other variable. However, passing the entire array requires that you pass a pointer-to-pointer to the array along with the dimension(s) of the array.


An array is a contiguous block of memory containing one or more elements of the same type. The array identifier is a reference to that block of memory. References do not require any memory other than the memory they reference. References are not variables -- they are merely aliases for memory addresses. A pointer is a variable that can store any reference and provides indirect access to that reference. Pointers can be used to allocate arrays dynamically, which means memory is required not only for the array, but also for the pointer to store the starting memory address of the array. Once allocated, the array can be referenced directly, but the pointer is still required in order to release the memory allocation when it is no longer required. Arrays employ pointer arithmetic to locate individual elements by their zero-based index, which is essentially an offset from the reference multiplied by the size of the element type. However arrays and pointers are not the same from a programming standpoint. Your compiler may well implement references as pointers, but that is only of concern to compiler authors, not programmers. Two-dimensional dynamic arrays make use of a pointer-to-pointer variable to point to a one-dimensional array of pointers, each of which points to a one-dimensional array of the actual elements. A three-dimensional array employs a pointer-to-pointer-to-pointer to point to a one-dimensional array of pointer-to-pointer variables, each of which points to a two-dimensional array. And so on. Static arrays use less memory as there is no need to maintain arrays of pointers, but static arrays are only useful when the number of elements and dimensions are known at compile time. At runtime, arrays of pointers are required over and above the array elements themselves, in order to both allocate and deallocate the memory, as well as obtain references to the elements in the array. Pointers also have uses beyond that of dynamic arrays, including allocating any type of memory of any size, and pointing at functions which can then be passed as arguments to other functions.


An array never behaves like a pointer.Understand that a pointer is a variable -- no different to any other variable, other than its type. like any other variable, it is allocated its own memory (4 bytes in a 32-bit system). Those 4 bytes can store any 32-bit value, from 0x00000000 to 0xFFFFFFFF, but because it is declared to be a pointer, that value actually represents a memory location, somewhere within the 4GB address space. 0x00000000 is a reserved memory location -- what we refer to as NULL.An array is not the same as a pointer in any sense. The array name refers to the actual memory (the starting address) where the array resides. But the array name is not a variable -- unlike a pointer, it is not separate from the memory it refers to -- it is merely an alias that refers to the memory allocated to the array itself.That said, pointers and arrays can appear to be the same. For instance, the strlen() function expects you to pass a const char pointer, and yet you can pass an array name instead and it works just fine:char cArray[12];char * p = cArray;strlen( p ); // Pass a pointerstrlen( &cArray[0] ); // Pass pointer to array element via AddressOf operatorstrlen( cArray ); // Pass an array nameAll three of these functions work exactly the same so it would be easy to assume the array is a type of pointer. But it is not. To understand what's really going on here you have to understand how pointers and arrays are actually passed to function.When you pass a pointer to a function, you don't pass the pointer itself, you pass the memory address stored in the memory allocated to the pointer. In other words, pointers are passed by value, not by reference. Similarly, when you pass an array name, you pass the starting address of the array.That's all there is to it! The function's parameter, a pointer, is allocated its own memory. It is a temporary variable, local to the function. All it expects is a memory location so whether you pass a pointer or an array name, that's exactly what it receives.



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