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To build a 64 to 1 multiplexer using cascaded 8 to 1 multiplexer, use nine 8 to 1's. Connect the first 8 to each of the 64 inputs, then connect the ninth to the outputs of the first eight. Connect the three address lines of the eight together to form 3 of the address lines. Connect the three address lines of the ninth to form the other three, for a total of 6 address lines selecting 1 of 64 inputs.

This is a lot of logic. Fan-in and fan-out may be considerations. If you are trying to scan 64 switches, there may be a better way using an 8-bit output connected to a switch matrix (with diodes if you need more than one at a time close-able) and then connected to an 8-bit input. Even better, consider the 8279 keyboard/display controller.

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14y ago
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11y ago

A multiplexer will have 2n inputs, n selection lines and 1 output.

A 16 input multiplexer accepts 16 inputs i. e. 24 and requires 4 selection lines.

An 8 input multiplexer accepts 8 inputs i. e. 23. And it needs 3 selection lines.

To realize a 16:1 multiplexer, two 8:1 multiplexers are required. They provide 16 inputs (8+8).

Join the three selection lines of each MUX. Now we require 16 combinations from selection lines. i. e.

0000, 0001, 0010, 0011, 0100, 0101, 0110, 0111

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1000, 1001, 1010, 1011, 1100, 1101, 1110, 1111

We know that 000, 001, 010, 011, 100, 101, 110,111 are common. Only the first bit differs (0 or 1). Hence, apply the fourth selection line as it is (i. e. 1) to upper 8:1 MUX and apply it complimented (i. e. 0) to lower MUX. Now it acts as 16:1 MUX.

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13y ago

Draw your truth table for the full adder, then incorporate the outputs of the full addder with the inputs of the multiplexer. when your finish you should be able to derive your boolean expressions from your truth table in order to design your circuit.

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13y ago

Theoretically you use five 4-to-1 multiplexers. You use four of them to connect the 16 inputs. You then have four outputs. Take the fifth multiplexer and connect the four outputs as the inputs. The fifth multiplexer then has a single output that has multiplexed the original 16 inputs.

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11y ago

A 8 1 MUX can easily be made by using two 4 1 MUX and a 2 1 MUX .....

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Is Multiplexer acts as not gate?

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