There are several methods for discussion read - I. Leguerinel, , I. Spegagne, O. Couvert, S. Gaillard and P. Mafart (2004) "Validation of an overall model describing the effect of three environmental factors on the apparent D-value of Bacillus cereus spores"International Journal of Food Microbiology
Volume 100, Issues 1-3, 15 April 2005, Pages 223-229
It means 75 degrees celcius.
The mass of copper is 240 g.Use the following formula:q = m x c x DeltaT,where:q is energy, m is mass, c is specific heat capacity, and DeltaT is the change in temperature.DeltaT = Tfinal-TinititalKnownq = 1200 calcCu = 0.0923 cal/g.oCTinitial = 20oCTfinal = 75oCDeltaT = 75oC - 20oC = 55oCUnknownmass of copperSolutionRearrange the equation q = m x c x DeltaT to isolate m. Plug in the known values and solve.m = q/(c x DeltaT)m = 1200/(0.0923 x 55) = 240 g (rounded to two significant figures)
Assuming copper conductor at 20 degrees celcius, you can use a chart to determine the resistance of a length of conductor. You must know it's size (AWG, for American wire gauge) and the look up the resistance per 1000 feet from any table. For a specific length of conductor, you just multiply the table's value by the proportion of 1000 feet that's actually the lenght of the conductor: table's resistance value x length in feet/1000 feet. For other temperatures or materials (i.e., aluminum), you must use a different formula: Rc = (K x L)/cmil where Rc = conductor resistance, K = "K factor" (see below), L = length of conductor and cmil is the cross sectional area of the conductor in circular mils (see the same chart referred to above). The K factor for different materials is Copper: 10.8@25OC, 11.8@50OC and 12.9@75OC Aluminum: 17.0@25OC, 19.0@50OC, 21.2@75OC The K factor is the resistance of one circular mil-foot (cmil-foot) of the material. A mil is 0.001" and a circular mil is a circle 1 mil in diameter. A circular mil-foot is a length of the material 1 circular mil in cross-sectional area and 1 foot long. The cmil value of a given wire gauge is the cross-sectional area in circular mils.
Fill up a small container (like your sink) with hot water. Make sure the bottle is tightly closed, so no water may get in, and let the bottle sit in the hot water for 5-10 minutes. The lotion is liquid again when you can shake the bottle and hear it moving.
The boiling point will increase with the addition of CaCl. I did an experiment where I added 13.002g of CaCl to 30mL of H2O and it raised the boiling point to 112oC. The initial reaction of CaCl and water produces heat in itself. The solution I used raised the water temperature to 75oC before the heat source was added to the water. I haven't experimented with the freezing point yet but I am assuming it will lower it because Calcium Chloride is an ionic salt and there is a tendency in ionic salts to lower the freezing point.