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This is the easiest way, though not "scientifically correct":

Liters concentrated HNO3 = [ 200 L diluted HNO3 * 10 % ] / [ 68% ] = 29.4 L of the 68%

Take the calculated amount and carefully add this to 171 L of water while good mixing!

(if you take 30 L (easier measurable!) in stead, then with 170 L water you get about 200 L of 10.2% diluted acid)

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Q: How do you dilute 68 percent of nitric acid to 200 liters of water if you want 10 percent concentration of nitric acid?
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