0
How can you make a three input OR gate with a two input OR gate?
Wiki User
∙ 12y ago
You would connect the output of the first AND gate to one input of the second AND gate. You are left with 2 inputs on the first AND gate and 1 input on the second AND gate. The final output is from the second AND gate.
Wiki User
∙ 13y ago
Wiki User
∙ 12y agoconnect the output of two input or gate with the two input or gate1.one input of or gate no.1 is output of or gate and another input is taken and hence final output of or gate no1 is formed three input or gate.
i.e
let o/p of or gate is A+B
which is one i/p of gate no1. and let another i/p is C.
and final i/p is Y=(A+B)+C=A+B+C
Add your answer:
Earn +20 pts
What is the ic number of and gate?
For two input AND gate it is 7408for three input AND gate it is 7411
How many 2-input and gates can replace n-input and gate Does that apply for nand gates as well?
for a two input gate to represent as an n-input gate excatly n-1 two input gates are required. this implies that for a two input OR gate to represent a four input OR gate exactly three two input OR gates are required let F is =a+b+c+d =(((a+b)+c)+d) =((a+b)+(c+d)) in both the above cases + is used three times so three two input OR gates make a four input OR gates. This discussion doesnot hold good for NAND gates an example can illlustrate the reson:- take F=(a.b.c.d)'=a'+b'+c'+d' --------------------------->(1) (this is obtained by a four input NAND gate) let us take this in the manner we did it for an OR gate and we will then verify the result. =((a.b)'(c.d)')' =((a'+b').(c'+d'))' =(a'+b')'+(c'+d')' =ab+cd <------------------------(2) (1)is not equal to (2) so we can say that a NAND gate cannot be replaced in the manner as OR gate is replaced
How many input take OR Gate?
It depends on the OR gate. Typically, there are two, three or four inputs, but sometimes there are more.
How many two input NAND gates are required to implement a four input NAND gates?
NOR gate = not(A or B) = A nor BAND gate = A and BAND gate = not(not A or not B)AND gate = not(not(A or A) or not(B or B))AND gate = (A nor A) nor (B nor B)Therefore using 2 input NORs to make a 2 input AND you need three NORs. If you wanted something different (e.g. a 5 input AND) the above proof can be modified appropriately to get your answer.
How do you convert a 4 input NOR gate into multiple 2 input NOR gate?
you will need 2 two input AND gates to do this. connect the output of the first to one input of the second. you now have a three input AND gate. just remember when calculating timing that 2 inputs of the 3 have twice the gate delay of the remaining input, thus the output will have skew and possibly glitches. if timing is critical or glitching can't be tolerated it may be best to use an actual three input AND instead of kludging one.
How do you convert not gate to ex or gate?
You can't make XOR out of NOT alone. Mathematically, NOT takes only a single argument, and its gate, an inverter, takes a single input. There's no way to combine two inputs giving a single output with one input gates. You need some two input gates to do the job. They can be AND, OR, NAND, NOR, or some combination, but you need something. That said, they don't have to be IC gates; you can combine two inputs with diodes to make an OR gate, so you could make XOR with only inverters and diodes, i.e. no other gate symbols on your schematic, but it would mot be making XOR out of NOT.
When is that the 'NAND' logic gate can function as a 'NOT' logic gate?
When the two input terminals of a NAND gate are short circuited, it acts as a NOT gate.
Give two ways of converting a two input NAND gate to an inverter?
Connect both inputs of the NAND gate together to form a single input. Tie one input of the NAND gate to a logic high (Vcc) and connect the other input to the desired input signal.
How can get and gate from nor gate?
an 2 input AND gate can be realize using 3 NOR gates.Let ,A and B are the input and x be the output.x=A.B= NOR(NOR(A) NOR(B))
How using two-input logic gates of your choice design a circuit to determine if two 3-bit numbers are the same or different?
Three 2-input XOR gates and one 3-input NOR gate will do the work. Connect each output of each XOR gate to one input of the 3-input NOR gate and apply the two 3-bit words to the inputs of the XOR gates. If X (X2X1X0) and Y(Y2Y1Y0) are two 3-bit words, X2 and Y2 will connect to one XOR gate, X1 and Y1 to the next XOR gate and X0 and Y0 to the last XOR gate. You could see the result of the operation on a LED connected to the output of the NOR gate. Other implementations are also possible of course. The solution above is absolutely correct, but includes a 3 input gate. If the task is to use only two input gates, then a small change will be needed. Take the outputs from any two XOR gates into a 2 input OR gate. Then take the output of the OR gate and the output of the third XOR gate into a 2 input NOR gate. The operation remains identical to the first solution but adheres to the brief of using gates with 2 inputs. In the real world, there is probably no reason to impose such a limitation on a design so the first solution would normally be the preferred route to take.
Describe the circuit implementation of function xy plus yz?
-- Take two 2-input AND gates.-- Attach 'y' to one input of one gate, and jumper that point toone input of the other gate.-- Attach 'x' to the free input of one gate, and attach 'z' to thefree input of the other gate.-- Attach the outputs of both gates to the inputs of a single OR gate.-- The output of the OR gate is the Boolean function ( XY + YZ ).=======================================Better implementation (faster, cheaper, easier to build, less hardware to fail):-- Attach 'x' and 'z' to the inputs of a single OR gate.-- Attach 'y' and the output of the OR gate to the two inputs of a single AND gate.-- The output of the AND gate is the same Boolean function.
What type of gate is the 74LS00?
The 74LS00 is a quad two input NAND gate with low power schottkey TTL implementation.
