In order to factor a quadratic formula with no coefficient on the first term, you'll need to find a pair of numbers whose product is your last term, and whose sum is the coefficient of your middle term. In the case of the given equation:
x2 + x + 3
This means we'll need a pair of numbers that add up to 1, and multiply to make 3. There are no numbers that meet this condition, which means that the given polynomial can not be factored.
(2x + 3)(x + 1)
Factor it. y(4y - 1)(3y - 2) = 0 y = 0, 1/4, 2/3
(-7x + 3)(-7x +3)
No.
(5*103)+(3*102) = 5300
(2x + 3)(x + 1)
(9+9)/3+3 =9
Factor it. y(4y - 1)(3y - 2) = 0 y = 0, 1/4, 2/3
5x^3(3x + 2)
That factors to 3(m - 4n)(6m - n)
10(2p + 3)(p + 4)
(-7x + 3)(-7x +3)
3 dB is a change in power by a factor of 2. If it is plus, i.e. +3dB, power is doubled. If it is minus, i.e. -3dB, power is halved. 6 dB, then is a factor of four, or quarter; 6 dB is a factor of eight, or eighth, etc. The actual equation is 3 log2 (POWER OUT / POWER IN).
(x + 3)(5x + 2)
No.
3x3 + 192 3(x3 + 64) ========
(5*103)+(3*102) = 5300