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Assume time = horizontal (x) axis, and velocity = vertical (y) axis. (Actually we should call it 'speed', since the graph conveys no information about the direction of the motion, only the speed. Similarly, the distance we'll find won't tell you how far from the starting point you wound up, only how much road or track you covered.) On the graph, there is some straight or wavy line representing your speed at every instant. -- Pick the starting time and ending time of the interval you're interested in. Draw vertical lines on the graph at the starting and ending times, long enough to cut the wavy line that represents the speed function. -- From the value of the function at the start-time, (the point where the 'start' vertical line cuts the graph of the function), draw a horizontal line, all the way across, to the 'end' vertical line. -- Now you must measure the area of the space bounded by the speed graph and the three straight lines you have drawn. This is easier if the graph was drawn on paper that is marked off in a grid of small squares. There may be places where the function is below the horizontal line, as well as places where the function is above it. If so, list the area of the space where the function is below the horizontal line as a negativenumber. -- When you're done, add up all the positive and negative pieces of area you have measured. The result is the total distance that the moving object traveled during the time between the 'start' and 'end' lines.
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What does a distance time graph allow you to find?
Besides obviously distance at any instant, on a connected, continuous distance-time graph, you can obtain instantaneous velocity and instantaneous acceleration.
In what kind of graph can you identify velocity?
A graph of distance against time.
What is the quantity which is measured by the area occupied below the velocity - time graph?
Distance travelled (displacement). Distance = velocity/time, so velocity * time = distance. Likewise, x = dv/dt so the integral of velocity with respect to time (area under the graph) is x, the distance travelled.
What is the slope in the distance time graph when the body is at rest?
the slope of distance time graph gives us velocity but when the body is at rest it will be zero
What are the advantages of velocity time graph?
Normally a position-time graph is actually a distance-time graph where the distance of an object is measured from a fixed point called the origin. The slope (gradient) of the graph is the radial velocity - or the component of the velocity in the radial direction - of the object. That is, the component of the object's velocity in the direction towards or away from the origin. Such a graph cannot be used to measure the component of the velocity at right angles to the radial direction. In particular, an object going around in a circle would appear t have no velocity since its distance from the origin remains constant.
What is the difference between a velocity time graph and a position time graph?
Simply put, a velocity time graph is velocity (m/s) in the Y coordinate and time (s) in the X and a position time graph is distance (m) in the Y coordinate and time (s) in the X if you where to find the slope of a tangent on a distance time graph, it would give you the velocity whereas the slope on a velocity time graph would give you the acceleration.
How do you go from a position graph to a velocity graph?
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.
What does a zero velocity graph look like?
In a velocity-time graph it will be the time axis (where velocity = 0). On a distance-time graph it will be a line parallel to the time axis: distance = some constant (which may be 0).
What does a distance time graph allow you to find?
Besides obviously distance at any instant, on a connected, continuous distance-time graph, you can obtain instantaneous velocity and instantaneous acceleration.
Calculate distance from a velocity time graph?
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity ÷ 2. Distance = average velocity * time. Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity ÷ 2) * time = ½ time * final velocity ...½ base * height = ½ time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.
In what kind of graph can you identify velocity?
A graph of distance against time.
How do you know there is no motion on a distance time-graph?
distance = velocity x time so on the graph velocity is slope. If slope is zero (horizontal line) there is no motion
Why is the distance time graph a straight line for?
A straight line on a distance - time graph represents a "constant velocity".
What is the quantity which is measured by the area occupied below the velocity - time graph?
Distance travelled (displacement). Distance = velocity/time, so velocity * time = distance. Likewise, x = dv/dt so the integral of velocity with respect to time (area under the graph) is x, the distance travelled.
How do you develop the general velocity equation from a Velocity vs Time graph?
Derivitives of a velocity : time graph are acceleration and distance travelled. Acceleration = velocity change / time ( slope of the graph ) a = (v - u) / t Distance travelled = average velocity between two time values * time (area under the graph) s = ((v - u) / 2) * t
What does the area of a velocity time graph gives?
Distance.
The slope of a line on a distance time graph?
Velocity.
