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N2 + 3H2 -> 2NH3

If you have moles produced you can do it this way.

22.5 moles NH3 (3 moles H2/2 moles NH3)

= 33.8 moles H2 needed

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Q: How do you find if you have 14.5 moles of N2 how many moles of H2 are theoretically needed to produce 22.5 moles of NH3 according to the reaction N2 plus 3H2 2NH3?
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