by using index position we can find the particular element in array.
It is the value of the element.
(array.length - 1) will find the index of the last element in an array (or -1 if the array is empty).
Basically, &array[i]; That is, the memory location for an array object with index i. Or, you can do: (array + i);
1010
You cannot delete from an array.
int findMax(int *array) { int max = array[0]; for(int i = 1; i < array.length(); i++) { if(array[i] > max) max = array[i] } return max; }
An array in C is structured so that it has no particular size; you have to know ahead of time what the dimensions are.So, a linear search means that you go from the first element to the last, either finding the element in the table, or going to the very last element and not finding it.Arrays in C can be zero-terminated, in which case you get the element that does not have a value, and that indicates the value you are searching for is not there.If the array is not zero terminated then you can calculate the dimension of the array, or apply the sizeof operator times the size of the first element to determine the length of the search.
which element of the array does this expression reference num[5]
for(int i = 0; i < [length][] ; i ++){ for(int j = 0; i < [][length]; i++){ if(array[i][j].equals(object)){ return true; } } } return false; Or something..
C-style example: sometype array [P][Q][R]; addr (array,I,J,K) = (char *)array + sizeof (sometype)*(I*Q*R + J*R + K)
The root of the tree is stored in array element [0]; for any node of the tree that is stored in array element [i], its left child is stored in array element [2*i], its right child at [2*i+2]
The search for the first array element begins at the assembly plant. As they array is being constructed, the element itself is one of the first components to be completed.