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How do you find the voltage at a point in a circuit with respect to a negative voltage?
First of all, 'voltage' means potential difference -and you cannot have a potential difference 'at a point'. Similarly, you cannot have a 'negative' potential difference, so it doesn't make sense to talk about a 'negative voltage'.Your question, therefore, should read: 'How do you find the potential at a point in a circuit with respect to a negative potential?'The answer is that you simply connect a voltmeter between the two points. The reading will give you the value of the potential. If it reads upscale, then it'll be positive; if it reads downscale, then it will be negative (i.e. even more negative tan the reference potential).
What are Ohms Law and the Power Law?
Ohms Law is used for the measurement of resistance. You can find the resistance in a series circuit using this equation; amps=volts/resistance or volts=amps x resistance.The Power Law is used to find the wattage in the circuit. You can find the amount of watts using this equation: watts=volts x amps.CommentOhm's Law has nothing whatsoever to do with either resistance or power.The equation, R = E/I, is derived from the definition of the ohm, and not from Ohm's Law.Ohm's Law simply describes a linear relationship between the potential difference across a conductor and the current through it. It does NOT describe the relationship between potential difference, current, and resistance.
Is a television a series circuit?
A television set is a complex group of circuits where we find components in series and others that are in parallel.
What is the potential difference and current characteristics in a series and parallel circuit?
In a simple parallel circuit -- for example, two resistors in parallel with a voltage source -- the voltage across the terminals of each component is the same. The current, however, 'splits' in order to take the two separate paths. In this case, you would use Ohm's law to find the current through each branch. In other words:I1=V/R1, I2=V/R2.If you have a current source instead of a voltage source, you would use current division to calculate current:I1=Isource*R2/(R1+R2), and I2=Isource*R1/(R1+R2).This is all in contrast with a simple series circuit, in which the current is the same through each component but the voltage drops are different. In which case you would use Ohm's law or Voltage division to calculate the individual voltages, depending on the source.
How to find Equivalent resistance when you have both parallel and series resistors?
To find equivalent resistance when you have both parallel and series resistors, start simple and expand... Find the smallest part of the circuit, such as a pair of resistors in series or a pair of resistors in parallel, and compute the equivalent single resistor value. Repeat that process, effectively covering more and more of the circuit, until you arrive at a single resistance that is equivalent to the circuit. For resistors in series: RTOTAL = R1 + R2 For resistors in parallel: RTOTAL = R1R2/(R1+R2)
Where is a voltmeter connected in a circuit?
Volt Meter is used to find the potential difference which is between the +ve or negative or between a Phase and Neutral etc. As it measure the potential difference, we need to connect in parallel which are tje extreme point of circuit starts and close, I mean completes.
How do you find the voltage at a point in a circuit with respect to a negative voltage?
First of all, 'voltage' means potential difference -and you cannot have a potential difference 'at a point'. Similarly, you cannot have a 'negative' potential difference, so it doesn't make sense to talk about a 'negative voltage'.Your question, therefore, should read: 'How do you find the potential at a point in a circuit with respect to a negative potential?'The answer is that you simply connect a voltmeter between the two points. The reading will give you the value of the potential. If it reads upscale, then it'll be positive; if it reads downscale, then it will be negative (i.e. even more negative tan the reference potential).
How do you find power in a series circuit?
Power dissipated by the entire series circuit = (voltage between its ends)2 / (sum of resistances of each component in the circuit). Power dissipated by one individual component in the series circuit = (current through the series circuit)2 x (resistance of the individual component).
What are Ohms Law and the Power Law?
Ohms Law is used for the measurement of resistance. You can find the resistance in a series circuit using this equation; amps=volts/resistance or volts=amps x resistance.The Power Law is used to find the wattage in the circuit. You can find the amount of watts using this equation: watts=volts x amps.CommentOhm's Law has nothing whatsoever to do with either resistance or power.The equation, R = E/I, is derived from the definition of the ohm, and not from Ohm's Law.Ohm's Law simply describes a linear relationship between the potential difference across a conductor and the current through it. It does NOT describe the relationship between potential difference, current, and resistance.
Can you find the potential difference when the charge is moving with external force?
ya:-):) because the charge q is proportional to potential difference
Where can you find a series circuit?
A lamp A fan and a bunch of other thingsAnswerThe classic example of a series circuit is a string of Christmas-tree lights. They are connected in series if, when one lamp burns out, all the lights go out.
What do you find out about the current at different places in the series circuit?
The current at different places in a series circuit is the same. Kirchoff's current law states that the signed sum of the currents entering a node is zero. A consequence of this is that the current at every point in a series circuit is the same.
Is a television a series circuit?
A television set is a complex group of circuits where we find components in series and others that are in parallel.
How do you find the power of a bulb when potential difference and current is given?
E = Voltage of the circuit I = Current in the circuit R = Resistance in the circuit Ohm's Law states that given two variables in an electric circuit, the third can be calculated: R=E/I I=E/R E=I*R Power in any circuit can be calculated by one of the following: P=E*I P=I2*R P=E2/R
What is the potential difference and current characteristics in a series and parallel circuit?
In a simple parallel circuit -- for example, two resistors in parallel with a voltage source -- the voltage across the terminals of each component is the same. The current, however, 'splits' in order to take the two separate paths. In this case, you would use Ohm's law to find the current through each branch. In other words:I1=V/R1, I2=V/R2.If you have a current source instead of a voltage source, you would use current division to calculate current:I1=Isource*R2/(R1+R2), and I2=Isource*R1/(R1+R2).This is all in contrast with a simple series circuit, in which the current is the same through each component but the voltage drops are different. In which case you would use Ohm's law or Voltage division to calculate the individual voltages, depending on the source.
How do you find the current in a wire?
Open the circuit and put an amp meter in series. There are clamp on current meters. You don't need to break the circuit.
A 12 volts power supply is connected across two resistors R1 120 ohms and R2 470 ohms in series Calculate the potential difference across each when the negative terminal of supply is earthed explain?
Earthing of the negative terminal is a common practice and will not affect the potential across the resistors in the circuit. Calculating this is simple Ohm's Law. For a series circuit: R(total) = R1 + R2 + R3....... Rn In this case: Rt = 120 + 470 = 590 ohms Per ohms law E = I x R. We need to find the current flowing throught the circuit so: I = E/R = 12 / 590 = .0203 amps or 20.3 milliamps The potential across an individual resistor is calculated again by E = I x R So for R1 (120 ohms): E1 = I x R1 = .0203 x 120 = 2.44 V So for R2 (470 ohms): E2 = I x R2 = .0203 x 470 = 9.54 V For a check E = E1 + E2 = 2.44 + 9.54 = 11.98 The .02 difference is due to the use of significant figures.Another AnswerEarthing the negative terminal will have no affect on the potential DIFFERENCE across each resistor. 'Potential' exists at a single point. 'Potential difference' exists between two points.
