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Specific gravity is equal to the density of the iron ore divided by the density of water. The densities change with temperature, so I will assume a temperature of 4 degrees C for this calculation. At this temperature the density of water is 1000kg/m^3. There are various types of iron ore with varying densities. I found a reference table that states the density if iron ore ranges from 2100 to 2900kg/m^3. I will use the average: 2400kg/m^3. The reference table doesn't give a temperature, but oh well. I would choose 4 degrees C if I could. This gives us:

specific gravity=(2400kg/m^3)/(1000kg/m^3)

=2.4

Notice there are no units. This is a dimensionless parameter. It says iron is 2.4 times as dense as water. It will sink.

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11y ago
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Q: How do you find specific gravity of Iron ore?
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