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To obtain the average velocity from a displacement-time graph, you can calculate the slope of the line connecting two points on the graph. Divide the change in displacement by the change in time. To obtain the instantaneous velocity, you need to find the slope of the tangent line at a specific point on the graph. Choose a point on the graph and draw a line tangent to the curve at that point. The slope of this tangent line will give you the instantaneous velocity at that specific point.
velocitymy answer isIt may be both speed/velocity.We can find acceleration from speed vs time graph when the path followed by the body is a perfect straight line and when the speed of body goes on incresing and in all othercases velocity time graph is used to measure aceleration.
You can't. However, you can find the change in speed between two points in time by finding the area under the acceleration-time graph.
Average speed = (total distance) / (total time) = (v1t1 + v2t2) / (t1 + t2)
there are a few equations: a=(v-u)/t v=utat s=ut+0.5at2 v2=u2+2as s=0.5(v+u).t Where: s=distance u=initial speed v=average speed a=acceleration t=time
The answer depends on what variables the graph shows.
-- Pick two points on the graph. -- Find the difference in time between the two points. -- Find the difference in displacement between the same two points. -- (Difference in displacement) divided by (difference in time) is the average Speed . You can't tell anything about velocity from the graph except its magnitude, because the graph displays no information regarding the direction of motion.
No. What you've described is instantaneous acceleration. To lift the average speed from a graph, you need a graph of distance-time. Pick two points in time, and find the distance at both those times. The average speed over that time interval is (difference between the distances at the beginning and end) divided by (difference between the two times). If you're just going for the average, then it doesn't matter what happened during the interval, only the values at the end-points. The slope of the line tangent to the curve on your distance-time graph is the instantaneous speed at that point in time. We're saying "speed" in this discussion because there's actually no such thing as a graph of velocity. No simple thing anyway. Velocity is a vector, whose magnitude is speed and which includes a direction. It's easy to graph speed vs time, but not that easy to graph direction vs time. So all the graph shows is speed.
Distance = time * average speed (velocity) Average speed = Distance/time
You can't, since the slope of the graph means average velocity and the area of the graph has no meaning. The only way to find instantaneous velocity from position-time gragh is by plugging the data into the kinematic equations to get the answer. Edit: Actually you can if you take the derivative of the equation of the curve it will give you the equation of the velocity curve
Assuming it's a graph of speed vs time, then between 2 times, the average is the distance (= area under the graph between those times) divided by the time difference.
To find the average speed or rate of something.(:
To find the average velocity of a projectile, use V = D/T (Velocity equals Displacement over Time).
Average speed = 1/2 (initial speed + final speed) Time = (distance)/(average speed)
Velocity is speed and direction
Average velocity is change in position (displacement) divided by the interval.
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.