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To find the average speed from a velocity-time graph, calculate the total distance traveled and divide it by the total time taken. This will give you the average speed. Alternatively, you can find the slope of the secant line that connects the initial and final points on the graph to determine the average speed.
What else can I help you with?
How can you get the speed of an object from its distance-time graph?
You can find the speed of an object from its distance-time graph by calculating the slope of the graph at a specific point. The slope represents the object's velocity at that particular moment. By determining the slope, you can find the speed of the object at that point on the graph.
How can you obtain the average velocity and instantaneous velocity from a displacement - time graph?
You cannot because a displacement-time graph is concerned only with radial motion: displacement from a fixed point of reference. Any transverse motion is completely ignored. Thus, if you had a body going around in a circle about the point of reference, its speed would be recorded zero!
How do you recognize acceleration on a graph?
Average Acceleration can be verbally defined as the change in velocity in a certain change in time... More simply put: Average Acceleration = (Final Velocity - Initial Velocity) / (Final Time - Initial Time)
Acceleration can be found by computing the slope of a vs. time graph.?
velocitymy answer isIt may be both speed/velocity.We can find acceleration from speed vs time graph when the path followed by the body is a perfect straight line and when the speed of body goes on incresing and in all othercases velocity time graph is used to measure aceleration.
How to find the velocity of a position-time graph?
To find the velocity of a position-time graph, you calculate the slope of the graph at a specific point. The slope represents the rate of change of position with respect to time, which is the velocity. The steeper the slope, the greater the velocity.
How do you find the average velocity on a graph?
The answer depends on what variables the graph shows.
How can you get the speed of an object from its distance-time graph?
You can find the speed of an object from its distance-time graph by calculating the slope of the graph at a specific point. The slope represents the object's velocity at that particular moment. By determining the slope, you can find the speed of the object at that point on the graph.
How can you obtain the average velocity from a displacement time graph?
-- Pick two points on the graph. -- Find the difference in time between the two points. -- Find the difference in displacement between the same two points. -- (Difference in displacement) divided by (difference in time) is the average Speed . You can't tell anything about velocity from the graph except its magnitude, because the graph displays no information regarding the direction of motion.
Is Average velocity the slope of the line tangent to the curve on a velocity-time graph at a specific instant of time?
No. What you've described is instantaneous acceleration. To lift the average speed from a graph, you need a graph of distance-time. Pick two points in time, and find the distance at both those times. The average speed over that time interval is (difference between the distances at the beginning and end) divided by (difference between the two times). If you're just going for the average, then it doesn't matter what happened during the interval, only the values at the end-points. The slope of the line tangent to the curve on your distance-time graph is the instantaneous speed at that point in time. We're saying "speed" in this discussion because there's actually no such thing as a graph of velocity. No simple thing anyway. Velocity is a vector, whose magnitude is speed and which includes a direction. It's easy to graph speed vs time, but not that easy to graph direction vs time. So all the graph shows is speed.
How can you obtain the average velocity and instantaneous velocity from a displacement - time graph?
You cannot because a displacement-time graph is concerned only with radial motion: displacement from a fixed point of reference. Any transverse motion is completely ignored. Thus, if you had a body going around in a circle about the point of reference, its speed would be recorded zero!
What is the formula to find the average speed of a given distance and time?
Distance = time * average speed (velocity) Average speed = Distance/time
How do you find average speed on a graph?
Assuming it's a graph of speed vs time, then between 2 times, the average is the distance (= area under the graph between those times) divided by the time difference.
How do you recognize acceleration on a graph?
Average Acceleration can be verbally defined as the change in velocity in a certain change in time... More simply put: Average Acceleration = (Final Velocity - Initial Velocity) / (Final Time - Initial Time)
How do you find instantaneous velocity from position time graph?
You can't, since the slope of the graph means average velocity and the area of the graph has no meaning. The only way to find instantaneous velocity from position-time gragh is by plugging the data into the kinematic equations to get the answer. Edit: Actually you can if you take the derivative of the equation of the curve it will give you the equation of the velocity curve
How is a distance time graph be used?
To find the average speed or rate of something.(:
Acceleration can be found by computing the slope of a vs. time graph.?
velocitymy answer isIt may be both speed/velocity.We can find acceleration from speed vs time graph when the path followed by the body is a perfect straight line and when the speed of body goes on incresing and in all othercases velocity time graph is used to measure aceleration.
How to find the velocity of a position-time graph?
To find the velocity of a position-time graph, you calculate the slope of the graph at a specific point. The slope represents the rate of change of position with respect to time, which is the velocity. The steeper the slope, the greater the velocity.
