It depends on where the rope is:
e.g. if an object is attached to a ceiling with a rope and we disregard the buoyancy force of air (in small cases we usually can) then F(tension)=mg(weight) but if its in a liquid being tied down to the floor then F(tension)=F(buoyancy)-mg(weight)- --> F(buoyancy) = ρ(density of the fluid)*V(the volume of the part of the object that is immersed in the liquid)*g
Naturally there are much more complex examples but these are the most common ones early in your physics education.
The direction of tension in a rope always runs both ways and parallel to the rope.
Assuming you meant two forces, the tension will be 200N.
Neglecting the weight of the rope itself, the tension will be 100 newton in any part of the rope.
In that case (ignoring the weight of the rope, for simplicity), the tension at any point of the rope will also be 100 N.
the tension in rope is equal to the sum of the two forces
Tension
the force of tension in the rope, which is delivered to the object to which the opposite end of the rope is attached
You get a tension in the chain or rope.
If the rope is hanging vertical ... one end from the ceiling and the other end to the bucket ... then the tension in the rope is 41.16 newtons (9.26 pounds).
In a rope with mass, the midpoint will have half the tension since it's only holding up half the mass.1kg x 9.8 m/s^2= 9.8N
The mountaineer kept tension on the rope so that his companion could climb to the ledge.
The breaking strength of the rope has to be stated in terms of the "tension" in the rope, and that has to be the 800N quoted here. If the ends of the rope are pulled in oppposite directions with a force of 500N on each end, then the tension in the rope at any point is 1000N, and yes, it will break.