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The generation of palindromic numbers within a given range is best done with a computer program. Space it limited so an example of program code cannot be shown here, but the Codecast website gives full guidance.
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C program to check whether the number and its reverse are same or not?
#include <stdio.h> #include<conio.h> void main () { int a,r,n,sum=0; clrscr(); printf("enter the number"); scanf("%d",& n); c=n while (n!=0) { a=n%10; n=n/10; sum=sum*a+a } printf("the reverse is %d \n",sum); if(c==sum) printf("\n the given number is palindrome"); else printf("\n the given number is not a palindrome"); getch(); }
Write a PHP program to check whether the number is palindrome or not?
This program only suits PHP. If you want a proper one try C program for it available on web <body> <?php if(isset($_POST['submit'])) { $text = $_POST['text']; $string = mysql_real_escape_string($text); $invert = strrev($string); if($string == $invert) { echo "<br>Given number is a palindrome!!"; } else { echo "<br>Given number is not a palindrome!!"; } } ?> <form method="post"> <input type="text" name="text" id="text" /> <input type="submit" name="submit" value="Submit" id="submit" onclick="<?php $_SERVER['PHP_SELF']; ?>" /> </form> </body>
Program to check palindrome using recursion?
#include <stdio.h> #include <conio.h> void main() { int num,rev=0,m,r; clrscr(); printf("enter any number"); scanf("%d",&num); m=num; while(num>0) { r=num%10; rev=rev*10+r; num=num/10; } if(rev==m) printf("given number is palindrome"); else printf("given number is not palindrome"); getch(); } this is the answer.
Program to check that given string is palindrome or not in C?
/*To check whether a string is palindrome*/includeincludevoid main () { int i,j,f=0; char a[10]; clrscr (); gets(a); for (i=0;a[i]!='\0';i++) { } i--; for (j=0;a[j]!='\0';j++,i--) { if (a[i]!=a[j]) f=1; } if (f==0) printf("string is palindrome"); else printf("string is not palindrome"); getch (); }
Write a c program that reverse a given integer number and check whether the number is palindrome or not?
#include <stdio.h> #include <string.h> #define N 100 #define PALINDROME 0 #define NONPALINDROME 1 /*Program that tells you whether what you enter is a palindrome or not*/ char pal[N]; //input line int i; //counter int k; //counter int tag; int flag = PALINDROME; /*flag=0 ->palindrome, flag =1 ->nonpalindrome*/ int main() { printf("Enter something: \n"); scanf("%s", pal); tag = strlen(pal); /*determine length of string*/ /* pointer running from the beginning and the end simultaneously looking for two characters that don't match */ /* initially assumed that string IS a palindrome */ /* the following for loop looks for inequality and flags the string as a non palindrome the moment two characters don't match */ for (i=0,k=tag-1; i=0; i++,k--) { if(pal[i] != pal[k]) { flag=NONPALINDROME; break; } } if(flag == PALINDROME) { printf("This is a palindrome\n"); } else { printf("This is NOT a palindrome\n"); } return 0; } #include <stdio.h> #include <string.h> #define N 100 #define PALINDROME 0 #define NONPALINDROME 1 /*Program that tells you whether what you enter is a palindrome or not*/ char pal[N]; //input line int i; //counter int k; //counter int tag; int flag = PALINDROME; /*flag=0 ->palindrome, flag =1 ->nonpalindrome*/ int main() { printf("Enter something: \n"); scanf("%s", pal); tag = strlen(pal); /*determine length of string*/ /* pointer running from the beginning and the end simultaneously looking for two characters that don't match */ /* initially assumed that string IS a palindrome */ /* the following for loop looks for inequality and flags the string as a non palindrome the moment two characters don't match */ for (i=0,k=tag-1; i=0; i++,k--) { if(pal[i] != pal[k]) { flag=NONPALINDROME; break; } } if(flag == PALINDROME) { printf("This is a palindrome\n"); } else { printf("This is NOT a palindrome\n"); } return 0; }
How can you generate a palindrome from a given number?
You write the number and then follow it with the digits in reverse order.
How do you determine if a given string is palindrome or not?
Reverse the string and compare it to the original. If they match, then it is a palindrome.
What is the palindrome for the kind of welcome given by a mayor?
civic
What is the palindrome for-type of welcome given by a mayor?
civic
What is the Palindrome that means the kind of welcome given by the mayor?
civic
What is a palindrome for type of welcome given by a mayor?
Civic
What is a palindrome for a kind of reception given by the mayor of a city?
A civic reception.
Which number is between the tow given number?
50 80
What is the difference between the greatest number and the least number in a given set of data?
depends on what the given set is
C program to check whether the number and its reverse are same or not?
#include <stdio.h> #include<conio.h> void main () { int a,r,n,sum=0; clrscr(); printf("enter the number"); scanf("%d",& n); c=n while (n!=0) { a=n%10; n=n/10; sum=sum*a+a } printf("the reverse is %d \n",sum); if(c==sum) printf("\n the given number is palindrome"); else printf("\n the given number is not a palindrome"); getch(); }
what is a number between each pair of number 2 and 3?
There are infinitely many number between the two given numbers.
Write a PHP program to check whether the number is palindrome or not?
This program only suits PHP. If you want a proper one try C program for it available on web <body> <?php if(isset($_POST['submit'])) { $text = $_POST['text']; $string = mysql_real_escape_string($text); $invert = strrev($string); if($string == $invert) { echo "<br>Given number is a palindrome!!"; } else { echo "<br>Given number is not a palindrome!!"; } } ?> <form method="post"> <input type="text" name="text" id="text" /> <input type="submit" name="submit" value="Submit" id="submit" onclick="<?php $_SERVER['PHP_SELF']; ?>" /> </form> </body>
