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The simplest answer is to XOR (eXclusive OR) each corresponding character. If the result is non-zero, you have a mismatch so you increment the count. Note that you must always loop through the shorter of the two strings. The difference in length is also a mismatch.
The following function shows the basic principal:
unsigned mismatch_count (const char* str1, const char* str2) {
/* some variables */
unsigned len, len1, len2, index, count;
/* determine length of each string */
len1=strlen (str1);
len2=strlen (str2);
/* store the shortest length */
len=len1<len2?len1:len2;
/* if the strings are different lengths, the difference is a mismatch */
count=(len==len1)?len2-len1:len1-len2;
/* XOR each corresponding character, incrementing the count when non-zero */
for (index=0; index<len; ++index) {
if ((str1[index]^str2[index])!=0) {
++count;
}
}
return count;
}
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