Use the array suffix operator ([]), or use a pointer offset from the start of the array, such that an offset of 1 is equivalent to the size of an array element (all elements in an array must be of equal size). The latter method is what actually goes on behind the scenes when using the array suffix operator, but the former is generally easier to use.
If you have array myArray of type int and size 3:
int myArray[3];
You can assign values to array:
myArray[0] = 1;
myArray[1] = 0;
myArray[2] = 13;
After you have assigned values to your array, you can get values in the same way as you would using variables (but you have to use index to access certain value):
int myInt1 = myArray[0];
...
The lowest subscript of an array in C, or C++ is 0.
How do you accept total no of array elements and values from the user in c?
yes
A multidimensional array in C or C++ is simply an array of arrays, or an array of an array of arrays, etc. for however many dimensions you want. int a; // not an array int a[10]; // ten int a's int a[10][20]; // twenty int a[10]'s, or 200 int a's int a[10][20][30]; // and so on and so forth...
int array[10] = {...}; for (int i = 0; i < 10; ++i) { if (i % 2 == 0) array[i] += 5; else array[i] -= 10; }
Put all the values in an array, iterate through the array with a for loop, sum all the values, then divide by the count of the values.
The lowest subscript of an array in C, or C++ is 0.
How do you accept total no of array elements and values from the user in c?
Heres something i whipped up in a hurry... This uses the Bubble Sort method found (related links) #include <iostream> using namespace std; int main(int argc, const char* argv) { int arraysize = 5; //Unsorted array size int array [] = { 5, 3, 4, 2, 1 }; //The array of numbers itself //Display the unsorted array cout << "Before: {"; for (int c=0; c <= arraysize; c++) { cout << array[c]; if (c != arraysize) { cout << ","; } } cout << "}" << endl; //Acctually sort the array int tmp=0; //Used for swaping values for (int loop=0; loop <= (arraysize - 1); loop++) { for (int c=0; c <= (arraysize - 1); c++) //The sort loop { if (array[c] > array[c + 1]) { //Swaps the two values in the array tmp = array[c]; array[c] = array[c + 1]; array[c + 1] = tmp; //Cleanup tmp = 0; } } } //Display the sorted array cout << "After: {"; for (int c=0; c <= arraysize; c++) { cout << array[c]; if (c != arraysize) { cout << ","; } } cout << "}" << endl; return 0; }
You cannot add elements to a fixed array in C or C++. If, however, the array is declared as a pointer to an array, you can add elements by allocating a new array, copying/adding elements as needed, reassigning the new array to the pointer, and deallocating the original array.
yes
A multidimensional array in C or C++ is simply an array of arrays, or an array of an array of arrays, etc. for however many dimensions you want. int a; // not an array int a[10]; // ten int a's int a[10][20]; // twenty int a[10]'s, or 200 int a's int a[10][20][30]; // and so on and so forth...
No.
A type construction: one or more values with the same type and name.
A type construction: one or more values with the same type and name.
int array[10] = {...}; for (int i = 0; i < 10; ++i) { if (i % 2 == 0) array[i] += 5; else array[i] -= 10; }
Every programming language treats strings as arrays. A C string is defined as being a null-terminated array of characters. A C string that does not have a null-terminator is just an array of character values, but without a null-terminator the onus is upon the programmer to keep track of the array's length.