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How do you isolate x in this equation 1 equals leftbracket 1 plus x right bracket exponent 5?
Wiki User
∙ 13y ago
with something called logarithms.
So 1 = (1 + x)^5
log 1 = log ((1+x)^5)
log 1 = 5 x log (1 +x)
but log 1 = 0
therefore 0 = 5 x log(1+x)
divide both sides by 5 and you get 0 = log (1+x)
we know that log 1 = 0, therefore 1+ x = 1 and so x = 0
Wiki User
∙ 13y ago
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