All resistors have a rating called 'maximum power dissipation', usually referred to as simply 'power'. Typical values are 1/8 watt, 1/4 watt, 1/2 watt, 1 watt, etc. up to many hundreds of watts for specialized resistors. Basically, if you exceed the power rating for a given resistor, it will fail. If you run it right at maximum power, it will work for a while, but will have a fairly short lifespan and will eventually fail (this is true for all electronic components for the most part). If you run it well below its maximum rating, it will pretty much last forever. Take a 10 ohm, 1 watt resistor and connect it to a 12 volt battery (hypothetically, that is, don't try this at home!) The current through the resistor will be: I=E/R I=12/10 I= 1.2 amperes The power dissipation will be: P=I^2 * R P=1.2^2 * 10 P=14.4 watts A 1 watt resistor that is dissipating 14.4 watts will fail in seconds, accompanied by smoke and quite possibly fire! Now connect a 270 ohm, 1 watt resistor to the 12 volt battery. The current: I=12/270 = 0.044 amperes (44 ma.) The power: P=0.044^2 * 270 = 0.52 watts This resistor will certainly get warm, but is operating well within its power rating and will last a long time.
This depends on the type of resistor. Carbon composition and metal film resistors typically will burn open, carbon film types can short.
Because if you dont you will burn and might get athsma Because if you dont you will burn and might get athsma Because if you dont you will burn and might get athsma
Led is a light emitting diodes which can two leads .one lead is larger and the other is smaller. You did't use any resistor because it glows with the small amount of energy! Idiot. I mean't how to I find out what my LED is. I know what a Led is and without a resistor, you prick, It wouldnt last a second.
if not disconnected you will measure the resistance of the circuit in parallel with the resistor.
Current flow. It's also worthy of noting that a resistor doesn't limit-by, it limits-to, and the current is dependent on the voltage. I[A] = U[V] / R[ohm] It's also worth to note, that the power flowing through said resistor with resistance R is I[A] * U[V] for DC circuits - helps to remember this well when picking appropriately-rated resistors for replacement. Example: let's say we have a 20-ohm, 2W resistor. If we place it in a circuit with 5V, we will get 5V / 20ohm = 250mA (0.25A) of current flowing through the resistor. The power the resistor will "see" is 250mA * 5V = 1.25W, so it's safe. But let's now put that same resistor in a 12V circuit. The current flowing will be 12V / 20ohm = 600mA (0.6A), and the power will be 600mA * 12V = 7.2W, so the resistor will burn.
A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor
This depends on the type of resistor. Carbon composition and metal film resistors typically will burn open, carbon film types can short.
Because if you dont you will burn and might get athsma Because if you dont you will burn and might get athsma Because if you dont you will burn and might get athsma
The old resistor was burned out. If you burn out the new one again, replace the blower motor.
cause its bad,replace with higher wattage rating.too much current !!
Yes it can. If there is a bad wire in your harness the ballast resistor will get hot, in which causes your coil to overheat and cut out or burn outline.
the year of the jeep is 1997 since the harness clip burn (i dont have the clip).. i dont know how to put cable back to the resistor it has 4 wire. from left to right please tell me which color goes were on the harness thank you You have got to say what year this is for. Not all years are the same. Thnks.
A malfunctioning blower motor resistor will cause the blower motor not to work. When the resistor is bad the blower motors will not turn on.
Most often a resistor fails because it is unable to properly dissipate the heat generated by the current flow. A resistor rated for more power (higher wattage) may resolve the problem.
Connecting an ammeter in parallel subjects that ammeter to the full supply voltage. The shunt resistor is not designed to sustain that value of voltage and will burn out. Also, the clue is in the word 'shunt' (which means 'in parallel') which means that the coil will also burn out!
If it's a fan speed issue check the blower motor resistor & the blower motor. Check the plugs at the resistor and blower motor for burn marks also.
You can only use a resistor to drop a voltage at a constant current. If you know the current, use Ohm's law to calculate the resistor value.