Power factor (PF) varies between 1 and zero. It is 1 for a pure resistive load. The closer to one the more efficient the system. Hence the ideal is to get PF to one. This isn't possible with an inductive load which causes current and voltage to be out of phase. Various circuits are used to try and correct PF to 1 to increase efficiency.
You can use the power factor correction to know if 1000kw is required in the kv capacitors.
The power factor for a three phase generator is 80 percent. The generator consumes 36 kilowatts and a line to line voltage of 400 volts.
Power factor doesn't apply to switches; it applies to loads.
Capacitor banks are used to control the power factor in a power system. By connecting suitable capacitors the power factor can be controlled / maintained at a desired level. The requirement of a capacitor changes as the load changes dynamically. The same amount of capacitors can not maintain the desired power factor all the time. To be able to connect only the required number of capacitors, multiple (bank of capacitors) capacitors are included in a system. An automatic controller senses the actual power factor and connects and disconnects the capacitors from the bank as required
Watts = Volts x Amps x Power Factor To make your calculation you need to plug-in the Voltage and Power factor. The Power Factor is a value from zero to one with one being a pure resistive load.
The ideal power factor is one (1) or 100% efficiency. Anything less than one means that extra power is required to achieve the actual task at hand. This extra energy, known as Reactive Power, is necessary to provide a magnetizing effect required by motors and other inductive loads to perform their desired functions.
The effect of low (or 'poor') power factor is that a given load requires more load current than at high power factors. So, to accommodate these higher currents, a greater volume of copper is required in the supply cables, switchgear, transformers, etc. So much greater capital costs are required if low power loads are supplied.
In order to answer this question, you need to know (a) its efficiency, and (b) its power factor at full load. 11 kW (not 'Kw') is its output power, so you need to know its efficiency in order to determine its input power. Then, because, for a three-phase system, power is equal to 1.732 times the product of the line voltage, line current, and power factor, you also need to know its power factor.
Watts = Volts x Amps x Power Factor. To answer your question requires that the Power Factor be know. The Power Factor ranges from zero to one and is one for a pure resistive load. If your device is resistive the answer is 1500 watts.
because we dont know power factor of the secondary laod
Watts = Voltage x Current x Power Factor 1000 Watts = 1 Kilowatt Therefore, you need to know current and Power Factor to answer your question.
When power factor is at unity, the voltage and current waves are aligned or in phase with one another. Since power is the product of voltage and current, power transfer is maximized at unity power factor. When power is transmitted at a lower power factor, greater current is required to deliver the same amount of power. When current is increased, the size of the transmission, distribution and generation systems, all have to be increased accordingly, along with the price of the killowatt-hour at the meter.