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Ammonium molybdate is (NH4)2MoO4. Its molar mass is 148g/mol. A 0.5M solution will have half a mole per liter of water. Half a mole of ammonium molybdate is 74g, so you would measure out 74g of it, and dissolve it in a liter of water.
Methane can be protonated by superacids to the carbonium ion: H+ + CH4 -> [CH5]+ So methane is a Lewis base but, like helium, it is an exceedingly feeble proton abstractor. and They can lose a proton, but their tendency to lose a proton is so small that the term acid would not normally be applied to them.
Necessary tests:- identification of sodium (by flamephotometry by ex.)- identifcation of the ion phosphate (add ammonium molybdate to the acidified solution: a yellow color appear)
Hydrochloric acid neutralises ammonium hydroxide to make ammonium chloride.
molybdate test is a test to detect the presence of phosphate at your solution and the appearance at the lab is purple pink as the phosphate is containing lipids and lipids will react with molybdate test to give pink color. Hope this answer you
Ammonium molybdate is (NH4)2MoO4. Its molar mass is 148g/mol. A 0.5M solution will have half a mole per liter of water. Half a mole of ammonium molybdate is 74g, so you would measure out 74g of it, and dissolve it in a liter of water.
Ammonium molybdate is (NH4)2MoO4. Its molar mass is 148g/mol. A 0.5M solution will have half a mole per liter of water. Half a mole of ammonium molybdate is 74g, so you would measure out 74g of it, and dissolve it in a liter of water.
Yellow Yellow
Yes
Ammonium molybdate is not considered a green chemical. It is a chemical compound that is commonly used as a catalyst, reagent, or analytical reagent. However, it has been classified as harmful to the environment and aquatic life, and therefore proper precautions should be taken when handling and disposing of it.
Tubidity with standard Ammonium Molybdate solution
Methane can be protonated by superacids to the carbonium ion: H+ + CH4 -> [CH5]+ So methane is a Lewis base but, like helium, it is an exceedingly feeble proton abstractor. and They can lose a proton, but their tendency to lose a proton is so small that the term acid would not normally be applied to them.
1 cm is .01m so 600cm*.01m = 6m =] -ray
Necessary tests:- identification of sodium (by flamephotometry by ex.)- identifcation of the ion phosphate (add ammonium molybdate to the acidified solution: a yellow color appear)
Hydrochloric acid neutralises ammonium hydroxide to make ammonium chloride.
.01m = 1cm
molybdate test is a test to detect the presence of phosphate at your solution and the appearance at the lab is purple pink as the phosphate is containing lipids and lipids will react with molybdate test to give pink color. Hope this answer you