Heres something i whipped up in a hurry...
This uses the Bubble Sort method found (related links)
#include <iostream>
using namespace std;
int main(int argc, const char* argv)
{
int arraysize = 5; //Unsorted array size
int array [] = { 5, 3, 4, 2, 1 }; //The array of numbers itself
//Display the unsorted array
cout << "Before: {";
for (int c=0; c <= arraysize; c++)
{
cout << array[c];
if (c != arraysize)
{
cout << ",";
}
}
cout << "}" << endl;
//Acctually sort the array
int tmp=0; //Used for swaping values
for (int loop=0; loop <= (arraysize - 1); loop++)
{
for (int c=0; c <= (arraysize - 1); c++) //The sort loop
{
if (array[c] > array[c + 1])
{
//Swaps the two values in the array
tmp = array[c];
array[c] = array[c + 1];
array[c + 1] = tmp;
//Cleanup
tmp = 0;
}
}
}
//Display the sorted array
cout << "After: {";
for (int c=0; c <= arraysize; c++)
{
cout << array[c];
if (c != arraysize)
{
cout << ",";
}
}
cout << "}" << endl;
return 0;
}
sorry
draw a flow chart to arrange 3 numbers in ascending order
addends
This is known as arranging the numbers in ascending order.
Ascending means increasing in value or moving higher, while descending means decreasing in value or moving lower. In a numeric sequence, ascending would go from lowest to highest, while descending would go from highest to lowest.
To arrange the numbers 7, 9, 56, and 72 in ascending order, you would start by comparing the numbers from left to right. The smallest number is 7, followed by 9, then 56, and finally 72. So, the numbers arranged in ascending order would be 7, 9, 56, and 72.
Arrange the numbers in ascending order, and then take the mean of the fourth and fifth number.
When you are given some numbers just arrange them in ascending order and you will the smallest number which can be made out of those given numbers.
In ascending order: 2.8, 8.02, 8.2, 22.8, 28.2
4.78 4.8 4.89 4.9 are the numbers arranged in ascending order.
To arrange numbers in ascending order in QBASIC, you can use a simple sorting algorithm like bubble sort. First, store the numbers in an array. Then, repeatedly compare adjacent elements and swap them if they are in the wrong order until the entire array is sorted. Here's a basic example: DIM numbers(5) AS INTEGER ' (Assume numbers are already populated) FOR i = 0 TO 4 FOR j = 0 TO 4 - i - 1 IF numbers(j) > numbers(j + 1) THEN SWAP numbers(j), numbers(j + 1) END IF NEXT j NEXT i This will sort the array numbers in ascending order.
To arrange numbers in ascending order using Java, you can utilize the Scanner class to read input from the user and then sort the numbers using an array. Here's a simple example: import java.util.Arrays; import java.util.Scanner; public class AscendingOrder { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("Enter the number of elements: "); int n = scanner.nextInt(); int[] numbers = new int[n]; System.out.println("Enter the numbers:"); for (int i = 0; i < n; i++) { numbers[i] = scanner.nextInt(); } Arrays.sort(numbers); System.out.println("Numbers in ascending order: " + Arrays.toString(numbers)); scanner.close(); } } This program collects a specified number of integers from the user, sorts them using Arrays.sort(), and then displays the sorted list.