How do you pass an array as a parameter?

Answer 1

Answer
Unfortunately your question is to broad. All progamming languages vary in the way things are done. I will just give a general way of doing it.
You have to pass the multidimensional array into the function by including it with calling the function. On the receiving end you have to declare another multidimensional array so the information can be passed into it. Depending on the language, you may not be passing in a multidimensional array, instead that array may be stored in an object which you can pass instead.
Hope this helps some.



-Ashat-
in C, when passing two dimensional arrays the compiler needs to know the width so it can calculate memory offsets.

passing a 2d array of width 4:

void
Func(type array[][4]);

Answer 2

In C, arrays are always passed by reference. This is, if you have an array value, and you pass it as the argument to a function, you are actually passing a pointer to the first element in the array, and modifications to the array from inside the function will be seen by the caller.

Answer 3

In C, all arrays implicitly convert to a pointer at the slightest provocation. As such, it is not possible to pass arrays by value (arrays cannot be copy-constructed), they must be passed by reference. Thus to accept an array, the function argument must be a pointer of the appropriate type. In cases where the size of the array cannot be deduced from the pointer alone, you must also pass the size of the array. Exceptions include null-terminated arrays, such as a null-terminated character array (a string), because the null-terminator marks the end of the array thus the size (if required) can be deduced.

In C++, we can pass arrays as objects, both by value and by reference. The standard template library provides three templates for arrays: std::array for fixed-length arrays; std::vector for variable-length arrays; and std::valarray for one-dimensional numeric matrices. We can also use C-style arrays as per C.