How do you prepare 0.1 M NaCl?

Answer 1

1. Weigh 58,44 g ultrapure NaCl dried at 110 0C for 30 min.
2. Transfer NaCl in a clean 1 L volumetric flask using a funnel. 3. Wash the funnel with 0,9 L demineralized water.
4. Put the flask in a thermostat and maintain 30 min at 20 0C.
5. Add demineralized water up to the mark.
6. Stir vigorously and transfer in a clean bottle with stopper.
7. Add a label with necessary information.

Answer 2

1. Weigh 58,44 g ultrapure NaCl dried at 110 0C for 30 min.
2. Transfer NaCl in a clean 1 L volumetric flask using a funnel.
3. Wash the funnel with 0,9 L demineralized water.
4. Put the flask in a thermostat and maintain 30 min at 20 0C.
5. Add demineralized water up to the mark.
6. Stir vigorously and transfer in a clean bottle with stopper.
7. Add a label with necessary information.

Answer 3

Sodium chloride molar mass is 58.44 g mol-1

You need to understand the concept first. M or Molarity means amount of substance concentration in 1 litre. For example, 1 M of NaCl is equal to 58.44 g of NaCl in 1 litre of water.

M, Molarity = Mol/Litre

Mol = substance weight/Molar Mass

0.1 M is equal to 0.1 mol, hence multiply 0.1 mol with molar mass you'll get 5.844 g

To prepare 0.1 M NaCl, weight out 5.844 g of NaCl and dilutes in 1 litre of water.

Answer 4

Dissolve 5,8439 g NaCl reagent grade in 1 L demineralized water at 20 0C.

Answer 5

Dissolve 58,4 mg pure sodium chloride in 1 L demineralized water at 20 0C.

Answer 6

Dissolve 0,05844 g of NaCl p.a. in 1 L demineralized water, at 20 0C, in a volumetric flask.

Answer 7

Dissolve 58,44 g NaCl reagent grade in 1 L demineralized water, at 20 0C, in a volumetric flak.

Answer 8

Dissolve 58,44 g NaCl pro analysis in 1 L demineralized water at 20 0C, in a volumetric flask.