we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
0,4 g NaOH + 1000 ml H2O
In order to make 0.02 N NaOH from 0.2 N NaOH, one needs to dilute it by 10 x (10 fold). Depending on the volume of 0.02 N NaOH needed, that will determine the volume of 0.2 N used. For example, to make 100 ml of 0.02 N NaOH, you would dilute 10 mls of 0.2 N to 100 ml. This is seen in the following calculation: (x ml)(0.2 N NaOH) = (100 ml) (0.02 N NaOH) and x = 10 ml
25 mL of 10% NaOH + 175 mL of distilled water
You need 2,4 g NaOH (0,06 moles).
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
0,4 g NaOH + 1000 ml H2O
Dissolve 0.4 g of NaOH in 100 ml of water. Try it out. Actually it is not suitable to prepare NaOH solutions in standard flasks.It should be made in beakers & must be standardised..This is done to find the correct normality...
In order to make 0.02 N NaOH from 0.2 N NaOH, one needs to dilute it by 10 x (10 fold). Depending on the volume of 0.02 N NaOH needed, that will determine the volume of 0.2 N used. For example, to make 100 ml of 0.02 N NaOH, you would dilute 10 mls of 0.2 N to 100 ml. This is seen in the following calculation: (x ml)(0.2 N NaOH) = (100 ml) (0.02 N NaOH) and x = 10 ml
25 mL of 10% NaOH + 175 mL of distilled water
20 grams of NaOH in 1000 ml water(1M)
You need 2,4 g NaOH (0,06 moles).
560 g in 350 ml (But I am not sure if that large quantity of NaOH will dissolve in 350 ml of wate).
Molartiy = moles of solute/Liters of solution200 mL X (1 Liter/10^2)= 0.200 Liters0.200 Liters x (0.05 M)= .01 moles of NaOH.01 moles of NaOH x (40 g NaOH/ 1 mole NaOH)= 0.4 g NaOH are required
(385 mL)(0.766 M NaOH) = (X mL)(4.03 M NaOH)4.03X = 294.91X = 73.2 ml============Take 73.2 mL of stock solution and add ( 385 mL - 73.2 mL = 311.8 mL) 312 mL of water to stock solution.
pH=10, so pOH=14-10=4 [OH]=10^-pOH [OH]=10^-4 [OH]=0.0001
Dissolve slowly 50 g NaOH in 100 mL water; advertisement: sodium hydroxide solution is dangerous !