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How do you prepare 2N ammonium hydroxide solution from 25 percent ammonium solution?
Wiki User
∙ 11y ago
Reference: the density of 25% NH4OH solution = 0.907g/cm³
Therefore 1 litre of solution has mass 907g
25% = 25/100*907 = 226.75g NH3 in 1 litre solution
Molar mass NH3 = 17.031 g/mol
226.75g = 226.75/17.031 = 13.31N solution
To make 1 litre of 2N solution: ( Work in ml= 1000ml)
N1V1 = N2V2
13.31*V1 = 2*1000
V1 = 2000/13.31
V1 = 150.2ml
Measure out 150.2ml of the 25% solution and dilute to 1 litre. This is a 2N solution.
Wiki User
∙ 11y ago
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