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How do you prepare 50 mM Sulphuric acid solution?
pl. suggest how to prepare 50 sulphuric acid
How do you prepare a 2 molar salicylic acid solution?
take 276 gm of salicylic acid in 1000 ml water to prepare 2M solution of the salicylic acid.
How do you prepare 0.25N sulphuric acid from 2N sulphuric acid?
You should dilute it 8 times.So get 250ml of 2N solution and add to 1L and 750ml of water.
What is the molar concentration of 99 percent solution of sulfuric acid?
Well if you have 99% solution of H2SO4, that means of one L you have 990 mL the acid. The density of sulphuric acid is 1.84g/mL... so that means you will have by mass 1821.6g of acid. The molecular weigth of H2SO4 is 98.1g/mol... so if you divide mass by molar mass you should get moles... which is about... 18.57moles. So that means 99% sulphuric acid is approx. 19M.
How to prepare nitrate test solution using diphenylamine in sulphuric acid?
Mix 90ml. sulfuric acid with 10ml. water, to this add 0.5gm. diphenylamine
How do you prepare 50 mM Sulphuric acid solution?
pl. suggest how to prepare 50 sulphuric acid
How do you prepare a 2 molar salicylic acid solution?
take 276 gm of salicylic acid in 1000 ml water to prepare 2M solution of the salicylic acid.
How do you prepare 0.25N sulphuric acid from 2N sulphuric acid?
You should dilute it 8 times.So get 250ml of 2N solution and add to 1L and 750ml of water.
What is the molar concentration of 99 percent solution of sulfuric acid?
Well if you have 99% solution of H2SO4, that means of one L you have 990 mL the acid. The density of sulphuric acid is 1.84g/mL... so that means you will have by mass 1821.6g of acid. The molecular weigth of H2SO4 is 98.1g/mol... so if you divide mass by molar mass you should get moles... which is about... 18.57moles. So that means 99% sulphuric acid is approx. 19M.
How to prepare nitrate test solution using diphenylamine in sulphuric acid?
Mix 90ml. sulfuric acid with 10ml. water, to this add 0.5gm. diphenylamine
Find volume of sulphuric acid of concentration 32 percent weight and density 1.531 gram per liter diluted to 5.8 liter to be 1.5 molar?
Initially, the mass of H2SO4 required to prepare 5.8 liters of 1.5 molar solution should be calculated. Number of moles present in 5.8 L of 1.5 molar solution = 1.5 mol L-1 x 5.8 L= 8.7 molMolar mass of H2SO4 = 98 g mol-1Therefore, mass of H2SO4 in the above solution = 8.7 mol x 98 g mol-1= 852.6 gMass of H2SO4 in the original solution per litre = 1.531 g x 32/100= 0.48992 gVolume of sulphuric acid required to prepare 1.5 molar solution = 852.6 g/0.48992 g = 1740.3 L
Is dilute sulphuric acid compound?
Dilute sulphuric acid is an aqueous solution, formed by adding water to sulphuric acid, resulting in a homogeneous mixture.
What is the mass of sulphuric acid?
The molar mass of sulfuric acid is 98 grams per mole.
What is the chemical equation for reaction between viscose solution and sulphuric acid?
write chemical equation for the reaction between viscose solution and sulphuric acid
WHAT IS THE chemical equation for the reaction between viscose solution and sulphuric acid?
write chemical equation for the reaction between viscose solution and sulphuric acid
How prepare 0.02 M H2So4?
0.02M sulphuric acid= molar mass x M x 1 litre = 98.08 x 0.02 x 1 =1.9616ml/l
What cannot be used with sulphuric acid to prepare zinc sulphate?
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