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To prepare a 2 molar sulfuric acid solution, you would need to measure out a specific amount of concentrated sulfuric acid and dilute it with the appropriate volume of water to achieve a final concentration of 2 moles per liter. It is crucial to add the acid to the water slowly and with stirring to prevent overheating and splashing. Always wear appropriate safety gear and handle concentrated acids with care.
What else can I help you with?
How do you prepare 0.25N sulphuric acid from 2N sulphuric acid?
To prepare 0.25N sulphuric acid from 2N sulphuric acid, you can dilute the 2N solution by adding 7 parts of water to 1 part of the 2N solution. This will result in a final 0.25N sulphuric acid solution.
How do you prepare 50 mM Sulphuric acid solution?
To prepare a 50 mM Sulphuric acid solution, you would need to calculate the required volume of concentrated Sulphuric acid (typically 96-98%) needed to dilute in water to achieve the desired concentration. You can use the formula: C1V1 = C2V2, where C1 is the concentration of the concentrated acid, V1 is the volume of concentrated acid needed, C2 is the desired concentration (50 mM), and V2 is the final volume of the solution you want to prepare.
What is the molar concentration of 99 percent solution of sulfuric acid?
Well if you have 99% solution of H2SO4, that means of one L you have 990 mL the acid. The density of sulphuric acid is 1.84g/mL... so that means you will have by mass 1821.6g of acid. The molecular weigth of H2SO4 is 98.1g/mol... so if you divide mass by molar mass you should get moles... which is about... 18.57moles. So that means 99% sulphuric acid is approx. 19M.
What colour would the red petal indicator be in a solution of sulphuric acid?
The red petal indicator would likely turn blue in a solution of sulphuric acid because sulphuric acid is a strong acid that would cause the indicator to change color.
How do you prepare a 2 molar salicylic acid solution?
To prepare a 2 molar salicylic acid solution, you would need to dissolve 17.5 grams of salicylic acid in enough water to make 1 liter of solution. First, measure out the salicylic acid using a balance, then add it to a beaker or flask with some water and stir until dissolved. Finally, add more water to bring the volume up to 1 liter, and mix well to ensure uniform concentration.
How do you prepare 0.25N sulphuric acid from 2N sulphuric acid?
To prepare 0.25N sulphuric acid from 2N sulphuric acid, you can dilute the 2N solution by adding 7 parts of water to 1 part of the 2N solution. This will result in a final 0.25N sulphuric acid solution.
How do you prepare 50 mM Sulphuric acid solution?
To prepare a 50 mM Sulphuric acid solution, you would need to calculate the required volume of concentrated Sulphuric acid (typically 96-98%) needed to dilute in water to achieve the desired concentration. You can use the formula: C1V1 = C2V2, where C1 is the concentration of the concentrated acid, V1 is the volume of concentrated acid needed, C2 is the desired concentration (50 mM), and V2 is the final volume of the solution you want to prepare.
What is the molar concentration of 99 percent solution of sulfuric acid?
Well if you have 99% solution of H2SO4, that means of one L you have 990 mL the acid. The density of sulphuric acid is 1.84g/mL... so that means you will have by mass 1821.6g of acid. The molecular weigth of H2SO4 is 98.1g/mol... so if you divide mass by molar mass you should get moles... which is about... 18.57moles. So that means 99% sulphuric acid is approx. 19M.
Is dilute sulphuric acid compound?
No. It is a mixture of sulphuric acid and water.
Find volume of sulphuric acid of concentration 32 percent weight and density 1.531 gram per liter diluted to 5.8 liter to be 1.5 molar?
Initially, the mass of H2SO4 required to prepare 5.8 liters of 1.5 molar solution should be calculated. Number of moles present in 5.8 L of 1.5 molar solution = 1.5 mol L-1 x 5.8 L= 8.7 molMolar mass of H2SO4 = 98 g mol-1Therefore, mass of H2SO4 in the above solution = 8.7 mol x 98 g mol-1= 852.6 gMass of H2SO4 in the original solution per litre = 1.531 g x 32/100= 0.48992 gVolume of sulphuric acid required to prepare 1.5 molar solution = 852.6 g/0.48992 g = 1740.3 L
What is the mass of sulphuric acid?
The molar mass of sulfuric acid is 98 grams per mole.
What cannot be used with sulphuric acid to prepare zinc sulphate?
Zinc oxide cannot be used with sulphuric acid to prepare zinc sulphate. This is because zinc oxide is insoluble in sulphuric acid, and therefore, it would not react to form zinc sulphate.
What is the chemical equation for reaction between viscose solution and sulphuric acid?
write chemical equation for the reaction between viscose solution and sulphuric acid
What colour would the red petal indicator be in a solution of sulphuric acid?
The red petal indicator would likely turn blue in a solution of sulphuric acid because sulphuric acid is a strong acid that would cause the indicator to change color.
How do you prepare a 2 molar salicylic acid solution?
To prepare a 2 molar salicylic acid solution, you would need to dissolve 17.5 grams of salicylic acid in enough water to make 1 liter of solution. First, measure out the salicylic acid using a balance, then add it to a beaker or flask with some water and stir until dissolved. Finally, add more water to bring the volume up to 1 liter, and mix well to ensure uniform concentration.
How we can prepare 10molar solution of acetic acid?
To prepare a 10M solution of acetic acid, dissolve 60.05g of glacial acetic acid (CH3COOH) in enough water to make a final volume of 1 liter. The molar mass of acetic acid is 60.05 g/mol. Make sure to wear appropriate safety gear, as acetic acid is corrosive.
How do you make 0.1 Molar of sulfuric acid?
9,8 g concentrated sulphuric acid to 1 L of water (attention to mixing !)
