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How many moles of sialicylic acid are in 2.5 grams of salicylic acid?
To determine the number of moles of salicylic acid in 2.5 grams, you need to divide the given mass by the molar mass of salicylic acid. The molar mass of salicylic acid is 138.12 g/mol. Therefore, 2.5 grams of salicylic acid is equal to 0.0181 moles.
Is salicylic acid acidic basic or neutral?
It is slightly basic. Behaves almost completely neutral.
Precipitate of salicylic acid dissolves after addition of excess sulphuric acid?
The precipitate of salicylic acid dissolves in excess sulphuric acid due to the formation of a complex between salicylic acid and sulphuric acid, which increases the solubility of the precipitate. This reaction results in the formation of a colorless solution, as the salicylic acid is converted into its conjugate base form.
How we can prepare 10molar solution of acetic acid?
To prepare a 10M solution of acetic acid, dissolve 60.05g of glacial acetic acid (CH3COOH) in enough water to make a final volume of 1 liter. The molar mass of acetic acid is 60.05 g/mol. Make sure to wear appropriate safety gear, as acetic acid is corrosive.
How do you prepare 2 molar sulphuric acid solution?
To prepare a 2 molar sulfuric acid solution, you would need to measure out a specific amount of concentrated sulfuric acid and dilute it with the appropriate volume of water to achieve a final concentration of 2 moles per liter. It is crucial to add the acid to the water slowly and with stirring to prevent overheating and splashing. Always wear appropriate safety gear and handle concentrated acids with care.
How do you prepare 1 m M solution of salicylic acid?
To prepare a 1 mM solution of salicylic acid, first calculate the mass required using the formula: mass (g) = molarity (mol/L) × volume (L) × molar mass (g/mol). The molar mass of salicylic acid is approximately 138.12 g/mol. For 1 liter of a 1 mM solution, you would need 0.1381 g of salicylic acid. Dissolve this mass in distilled water and then dilute to a total volume of 1 liter.
How do you prepare standard solution of salicylic acid for siderophore estimation?
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How many moles of sialicylic acid are in 2.5 grams of salicylic acid?
To determine the number of moles of salicylic acid in 2.5 grams, you need to divide the given mass by the molar mass of salicylic acid. The molar mass of salicylic acid is 138.12 g/mol. Therefore, 2.5 grams of salicylic acid is equal to 0.0181 moles.
Is salicylic acid acidic basic or neutral?
It is slightly basic. Behaves almost completely neutral.
What is your expected yield of aspirin in grams if you use 5.452g of salicylic acid in your reaction?
To calculate the expected yield of aspirin from 5.452 g of salicylic acid, we first need to determine the molar mass of salicylic acid (C7H6O3), which is approximately 138.12 g/mol. The reaction to produce aspirin (acetylsalicylic acid) involves the acetylation of salicylic acid, yielding one mole of aspirin for each mole of salicylic acid used. Assuming 100% yield, using 5.452 g of salicylic acid would theoretically produce about 5.452 g of aspirin, as the molar mass of aspirin is also similar (approximately 180.16 g/mol).
Precipitate of salicylic acid dissolves after addition of excess sulphuric acid?
The precipitate of salicylic acid dissolves in excess sulphuric acid due to the formation of a complex between salicylic acid and sulphuric acid, which increases the solubility of the precipitate. This reaction results in the formation of a colorless solution, as the salicylic acid is converted into its conjugate base form.
How we can prepare 10molar solution of acetic acid?
To prepare a 10M solution of acetic acid, dissolve 60.05g of glacial acetic acid (CH3COOH) in enough water to make a final volume of 1 liter. The molar mass of acetic acid is 60.05 g/mol. Make sure to wear appropriate safety gear, as acetic acid is corrosive.
Calculate the amount of salicylic acid needed in 1 percent ointment that will be 15 g in size?
To prepare a 1% salicylic acid ointment that is 15 g in size, you would need 0.15 g of salicylic acid. This is calculated by multiplying 15 g by 0.01 (1%). Therefore, 0.15 g of salicylic acid would be required for the preparation.
How do you prepare 2 molar sulphuric acid solution?
To prepare a 2 molar sulfuric acid solution, you would need to measure out a specific amount of concentrated sulfuric acid and dilute it with the appropriate volume of water to achieve a final concentration of 2 moles per liter. It is crucial to add the acid to the water slowly and with stirring to prevent overheating and splashing. Always wear appropriate safety gear and handle concentrated acids with care.
Calculate the required amount of oxalic aciddihydrate to prepare 200 mL of 0.50M oxalic acid solution?
To prepare 200 mL of 0.50M oxalic acid solution, you would need 0.1 moles of oxalic acid. Since oxalic acid is a dihydrate (H2C2O4·2H2O), you would need to account for the water content. The molar mass of oxalic acid dihydrate is 126.07 g/mol, so you would need 12.607 grams of oxalic acid dihydrate to prepare the solution.
What is the molar concentration of nitric acid?
The molar concentration of nitric acid can vary depending on the specific solution. However, a common concentration of nitric acid used in laboratories is around 16 M (molar). This means there are 16 moles of nitric acid in 1 liter of solution.
What is the physical state of salicylic acid?
Salicylic acid is a solid at room temperature.
