take 276 gm of salicylic acid in 1000 ml water to prepare 2M solution of the salicylic acid.
To determine the number of moles of salicylic acid in 2.5 grams, you need to divide the given mass by the molar mass of salicylic acid. The molar mass of salicylic acid is 138.12 g/mol. Therefore, 2.5 grams of salicylic acid is equal to 0.0181 moles.
It is slightly basic. Behaves almost completely neutral.
The precipitate of salicylic acid dissolves in excess sulphuric acid due to the formation of a complex between salicylic acid and sulphuric acid, which increases the solubility of the precipitate. This reaction results in the formation of a colorless solution, as the salicylic acid is converted into its conjugate base form.
To prepare a 10M solution of acetic acid, dissolve 60.05g of glacial acetic acid (CH3COOH) in enough water to make a final volume of 1 liter. The molar mass of acetic acid is 60.05 g/mol. Make sure to wear appropriate safety gear, as acetic acid is corrosive.
To prepare a 2 molar sulfuric acid solution, you would need to measure out a specific amount of concentrated sulfuric acid and dilute it with the appropriate volume of water to achieve a final concentration of 2 moles per liter. It is crucial to add the acid to the water slowly and with stirring to prevent overheating and splashing. Always wear appropriate safety gear and handle concentrated acids with care.
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To determine the number of moles of salicylic acid in 2.5 grams, you need to divide the given mass by the molar mass of salicylic acid. The molar mass of salicylic acid is 138.12 g/mol. Therefore, 2.5 grams of salicylic acid is equal to 0.0181 moles.
It is slightly basic. Behaves almost completely neutral.
The precipitate of salicylic acid dissolves in excess sulphuric acid due to the formation of a complex between salicylic acid and sulphuric acid, which increases the solubility of the precipitate. This reaction results in the formation of a colorless solution, as the salicylic acid is converted into its conjugate base form.
To prepare a 10M solution of acetic acid, dissolve 60.05g of glacial acetic acid (CH3COOH) in enough water to make a final volume of 1 liter. The molar mass of acetic acid is 60.05 g/mol. Make sure to wear appropriate safety gear, as acetic acid is corrosive.
To prepare a 1% salicylic acid ointment that is 15 g in size, you would need 0.15 g of salicylic acid. This is calculated by multiplying 15 g by 0.01 (1%). Therefore, 0.15 g of salicylic acid would be required for the preparation.
To prepare a 2 molar sulfuric acid solution, you would need to measure out a specific amount of concentrated sulfuric acid and dilute it with the appropriate volume of water to achieve a final concentration of 2 moles per liter. It is crucial to add the acid to the water slowly and with stirring to prevent overheating and splashing. Always wear appropriate safety gear and handle concentrated acids with care.
To prepare 200 mL of 0.50M oxalic acid solution, you would need 0.1 moles of oxalic acid. Since oxalic acid is a dihydrate (H2C2O4·2H2O), you would need to account for the water content. The molar mass of oxalic acid dihydrate is 126.07 g/mol, so you would need 12.607 grams of oxalic acid dihydrate to prepare the solution.
The molar concentration of nitric acid can vary depending on the specific solution. However, a common concentration of nitric acid used in laboratories is around 16 M (molar). This means there are 16 moles of nitric acid in 1 liter of solution.
Salicylic acid is a solid at room temperature.
Measure equal amounts sand and salicylic acid and mix thorougly. Place the mixture in a test tube or some type of glass container. add ethanol stir with a stirring rod. allow the sand to settle to the bottom of the container and then pour out the mixture over a filter into another glass container, and now the sand is separated from the salicylic acid.If you need the salicylic acid, just boil the leftover solution until all the ethanol boils out.
To prepare a 1 molar (1 M) solution of a substance, you need to know its molar mass. The molar mass of acetic acid (CH₃COOH) is approximately 60.05 g/mol. Therefore, to make 1 liter of a 1 M solution, you would need 60.05 grams of acetic acid. If you meant a different substance by "ACLU," please specify for an accurate calculation.