1.Weigh 292,2 g ultrapure NaCl dried at 110 0C for 30 min.
2. Transfer NaCl in a clean 1 L volumetric flask usig a funnel and demineralized water up to 0,9 L.
3. Put the flask in a thermostat and maintain 30 min at 20 0C.
4. Add demineralized water up to the mark.
5. Stir vigorously and transfer in a clean bottle with stopper.
6. Add a label with necessary informatio
Dissolve 292,2 g NaCl reagent grade in 1 L demineralized water, at 20 0C.
Dissolve 0,35064 g NaCl in demineralized water, at 20 0C in a volumetric flask.
Dissolve 584,4 mg NaCl in 1 L demineralized water, at 20 0C, in a volumetric flask.
Dissolve 58,44 mg NaCl in 1 L of demineralized water, at 20 0C, in a volumetric flask.
Dissolve o,29 g NaCl in 1 L water.
You have to dilute the 10 mM NaCl 100X, 33,333X and 10X (X means "times") e.g. 100X: mix 10 ml of 10 mM Nacl with 990 ml of water (= 0,1 mM) 33,333X: mix 30 ml of 10 mM NaCl with 970 ml of water (= 0,3 mM) 10X: mix 100 ml of 10 mM NaCl with 900 ml of water (= 1 mM)
A water solution containing 50 mM tris(hydroxymethyl)aminomethane and 150 mM sodium chloride has a pH of 7,6.
For 100 mM NaCl solution in 1L: Formula weight: 58.44 g/L Answer: 5.844 g/L if you want in 500 mL---2.922 g if you want in 250 mL---1.461 g if you want in 100 mL---584.4 mg
Also 150 mM of sodium.
Dissolve 50 mg NaCl pro analysis in 1 L demineralized water, at 20 0C, in a volumetric flask.
500 mm = 5 dm
The hypotenuse of a triangle with a base of 300 mm and 500 mm height is: 583.1 mm
500 cm = 5 000 mm
They are equal. 10 mm = 1 cm 500 mm = 50 cm
10 mm = 1 cm so 500 mm = 50 cm. Simple!
500 millimeters are 19.685039 inches. Direct Conversion Formula 500 mm* 1 in 25.4 mm = 19.68503937 in
500 mm is equal to 19.6850393700787 inDirect Conversion Formula 500 mm*1 in25.4 mm=19.68503937 in