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1.Weigh 292,2 g ultrapure NaCl dried at 110 0C for 30 min.
2. Transfer NaCl in a clean 1 L volumetric flask usig a funnel and demineralized water up to 0,9 L.
3. Put the flask in a thermostat and maintain 30 min at 20 0C.
4. Add demineralized water up to the mark.
5. Stir vigorously and transfer in a clean bottle with stopper.
6. Add a label with necessary informatio
What else can I help you with?
How do you prepare TRIS-NaCl?
A water solution containing 50 mM tris(hydroxymethyl)aminomethane and 150 mM sodium chloride has a pH of 7,6.
How do you prepare 0.1mM 0.3mM and 1mM from 10mM of NaCl?
Oh, dude, it's like making a fancy cocktail but with salt. So, for 0.1mM, you just take 1 part of the 10mM NaCl and mix it with 9 parts of water. For 0.3mM, it's 3 parts NaCl and 7 parts water. And for 1mM, it's just 1 part NaCl and 9 parts water. Easy peasy, lemon squeezy!
How much NaCl is required for 100 mM NaCl solution?
To prepare a 100 mM NaCl solution, you would need to calculate the molecular weight of NaCl, which is approximately 58.44 g/mol (sodium's atomic weight is 22.99 g/mol and chlorine's is 35.45 g/mol). To make a 100 mM solution, you would need 0.1 moles of NaCl per liter of solution. This would be equivalent to 5.844 grams of NaCl per liter of solution.
How many mM OF Na are in 150 mM NaCl solution?
Also 150 mM of sodium.
How do you prepare 50 ppm sodium from nacl?
Dissolve 50 mg NaCl pro analysis in 1 L demineralized water, at 20 0C, in a volumetric flask.
How many dm equal 500 mm?
500 mm = 5 dm
500 mm equals how many inches?
500 millimeters are 19.685039 inches. Direct Conversion Formula 500 mm* 1 in 25.4 mm = 19.68503937 in
What is the hypotenuse of a triangle with a base of 300 mm and 500 mm height?
The hypotenuse of a triangle with a base of 300 mm and 500 mm height is: 583.1 mm
What is larger 500 cm or 5000 mm?
500 cm = 5 000 mm
Which is larger 500 mm or 50 cm?
They are equal. 10 mm = 1 cm 500 mm = 50 cm
How many centimeters are in 500 mm?
10 mm = 1 cm so 500 mm = 50 cm. Simple!
How many grams of Na Cl molecular weight 58.5 g mole -1 would you dissolve in water to make a 50 mM Na Cl solution with 500 ml final volume?
By definition, a 50 mM solution of any substance contains 50 mM of the solute per liter of solution, and true solutions are always homogeneous mixtures. Therefore, 500 ml of such a solution would contain (50)(500/1000) or 2.50 millimoles of NaCl. The molecular weight of the salt Is stated in the question to be 58.5 grams per mole; therefore, the millimolecular mass would be 58.5 milligrams; and 2.50 times that value or 146 mg, to the justified number of significant digits , would be contained in 500 ml of the solution and would need to be supplied from the stock of NaCl available.
