1.Weigh 292,2 g ultrapure NaCl dried at 110 0C for 30 min.
2. Transfer NaCl in a clean 1 L volumetric flask usig a funnel and demineralized water up to 0,9 L.
3. Put the flask in a thermostat and maintain 30 min at 20 0C.
4. Add demineralized water up to the mark.
5. Stir vigorously and transfer in a clean bottle with stopper.
6. Add a label with necessary informatio
A water solution containing 50 mM tris(hydroxymethyl)aminomethane and 150 mM sodium chloride has a pH of 7,6.
You have to dilute the 10 mM NaCl 100X, 33,333X and 10X (X means "times") e.g. 100X: mix 10 ml of 10 mM Nacl with 990 ml of water (= 0,1 mM) 33,333X: mix 30 ml of 10 mM NaCl with 970 ml of water (= 0,3 mM) 10X: mix 100 ml of 10 mM NaCl with 900 ml of water (= 1 mM)
To prepare a 100 mM NaCl solution, you would need to calculate the molecular weight of NaCl, which is approximately 58.44 g/mol (sodium's atomic weight is 22.99 g/mol and chlorine's is 35.45 g/mol). To make a 100 mM solution, you would need 0.1 moles of NaCl per liter of solution. This would be equivalent to 5.844 grams of NaCl per liter of solution.
Also 150 mM of sodium.
Dissolve 50 mg NaCl pro analysis in 1 L demineralized water, at 20 0C, in a volumetric flask.
By definition, a 50 mM solution of any substance contains 50 mM of the solute per liter of solution, and true solutions are always homogeneous mixtures. Therefore, 500 ml of such a solution would contain (50)(500/1000) or 2.50 millimoles of NaCl. The molecular weight of the salt Is stated in the question to be 58.5 grams per mole; therefore, the millimolecular mass would be 58.5 milligrams; and 2.50 times that value or 146 mg, to the justified number of significant digits , would be contained in 500 ml of the solution and would need to be supplied from the stock of NaCl available.
500 mm = 5 dm
500 millimeters are 19.685039 inches. Direct Conversion Formula 500 mm* 1 in 25.4 mm = 19.68503937 in
The hypotenuse of a triangle with a base of 300 mm and 500 mm height is: 583.1 mm
To prepare a 1 liter of 100ppm NaCl solution, you would dissolve 0.1 grams of NaCl in 1 liter of water. This concentration is achieved by mixing 0.1 grams of NaCl in 1 liter of water.
500 cm = 5 000 mm
They are equal. 10 mm = 1 cm 500 mm = 50 cm