By definition, a 50 mM solution of any substance contains 50 mM of the solute per liter of solution, and true solutions are always homogeneous mixtures. Therefore, 500 ml of such a solution would contain (50)(500/1000) or 2.50 millimoles of NaCl. The molecular weight of the salt Is stated in the question to be 58.5 grams per mole; therefore, the millimolecular mass would be 58.5 milligrams; and 2.50 times that value or 146 mg, to the justified number of significant digits , would be contained in 500 ml of the solution and would need to be supplied from the stock of NaCl available.
5.85gms/500cc
14.625
use the equation that is standard: 1000 ml 1 M solution= (MOLECULAR WEIGHT) X ml 0.05 M solution = ((MOLECULAR WEIGHT)*X*0.05)/1000
Calculate the weight of sucrose for the desired volume and concentration of the solution.
Take 5 grams of calcium chloride and dissolve it in 100ml of solution to get a 5% solution of calcium chloride. The standard way to make a weight-volume solution is to take grams of the dry substance in 100ml of volume.
5.85gms/500cc
14.625
You know the chemical formula. You can get the molecular weight from this. You need the end volume and you also need the mass of solute.
The volume of a gas is not directly proportional to its molecular weight.
the given molecular weight is divided by volume
how to prepare .05M glutaraldhyde solution molecular weight is 100.12
This is easy if a gas. The weight of a volume of 22.41 L will give the molecular mass.
molarity x molecular weight x volume=gram molarity= gram/molecular weight x volume abdulrazzaq
Molarity = Grams/(Molecular Weight X Volume)
Molarity = Grams/(Molecular Weight X Volume)
Iron (III) chloride has the molecular formula of FeCl3. Its molecular weight is 162.2 grams per mole. Concentration is moles of solute divided by volume of solution. Therefore, the answer is .224 moles per liter.
use the equation that is standard: 1000 ml 1 M solution= (MOLECULAR WEIGHT) X ml 0.05 M solution = ((MOLECULAR WEIGHT)*X*0.05)/1000