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By definition, a 50 mM solution of any substance contains 50 mM of the solute per liter of solution, and true solutions are always homogeneous mixtures. Therefore, 500 ml of such a solution would contain (50)(500/1000) or 2.50 millimoles of NaCl. The molecular weight of the salt Is stated in the question to be 58.5 grams per mole; therefore, the millimolecular mass would be 58.5 milligrams; and 2.50 times that value or 146 mg, to the justified number of significant digits , would be contained in 500 ml of the solution and would need to be supplied from the stock of NaCl available.

Q: How many grams of Na Cl molecular weight 58.5 g mole -1 would you dissolve in water to make a 50 mM Na Cl solution with 500 ml final volume?

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You would need to dissolve 14.62 grams of NaCl in water to make a 0.5M NaCl solution with a final volume of 500 ml. This calculation is based on the formula: moles = Molarity x Volume (in liters), and then converting moles to grams using the molecular weight of NaCl.

To make a 5% (w/v) solution, you would dissolve 25 grams of sodium chloride (5% of 500 grams) in water to make a final volume of 500 mL. Sodium chloride has a molecular weight of 58.5 g/mol.

To make a percent sucrose solution, dissolve a specific weight of sucrose in a specific volume of water. For example, to make a 10% sucrose solution, dissolve 10 grams of sucrose in 90 mL of water. The formula to calculate the amount of sucrose needed is: (percent sucrose/100) x volume of solution = weight of sucrose (in grams).

To prepare a 0.2 millimolar (mM) DPPH solution in ethanol, you need to dissolve 0.2 millimoles of DPPH in a final volume of 1 liter of ethanol. First, calculate the molecular weight of DPPH (usually around 394.33 g/mol) to determine the mass needed to dissolve in ethanol. Then add this mass of DPPH to ethanol and make up the volume to 1 liter.

To prepare a 0.0500 M sodium carbonate solution, you would need to accurately weigh out the required amount of anhydrous sodium carbonate (Na2CO3), dissolve it in a known volume of water, and then dilute to the appropriate final volume while ensuring thorough mixing to achieve homogeneity. Make sure to use appropriate glassware and techniques to maintain accuracy.

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You would need to dissolve 14.62 grams of NaCl in water to make a 0.5M NaCl solution with a final volume of 500 ml. This calculation is based on the formula: moles = Molarity x Volume (in liters), and then converting moles to grams using the molecular weight of NaCl.

To make a 5% (w/v) solution, you would dissolve 25 grams of sodium chloride (5% of 500 grams) in water to make a final volume of 500 mL. Sodium chloride has a molecular weight of 58.5 g/mol.

To determine the molarity of a solution when the chemical formula of the solute is known, you need to know the mass of the solute dissolved in the solution and the volume of the solution. From there, you can use the formula: Molarity = (moles of solute) / (volume of solution in liters) to calculate the molarity of the solution.

To make a 0.25N K2CrO4 solution, you need to first calculate the molecular weight of K2CrO4 (potassium chromate). Then, determine the grams of K2CrO4 needed to make the desired volume of solution at a concentration of 0.25N. Dissolve this amount of K2CrO4 in the required volume of solvent, usually water, to make the final solution.

To prepare a 10mM ferric chloride solution, first calculate the molecular weight of FeCl3 to determine the amount needed to achieve a concentration of 10mM. Dissolve this amount in a known volume of water or solvent to make up the final volume of the solution, ensuring thorough mixing to achieve homogeneity.

To make a percent sucrose solution, dissolve a specific weight of sucrose in a specific volume of water. For example, to make a 10% sucrose solution, dissolve 10 grams of sucrose in 90 mL of water. The formula to calculate the amount of sucrose needed is: (percent sucrose/100) x volume of solution = weight of sucrose (in grams).

To prepare a 0.5M glutaraldehyde solution, you would need to dilute a concentrated glutaraldehyde stock solution with the appropriate volume of water or buffer solution. Calculate the volume of stock solution needed based on the desired final volume and concentration, then dilute with the solvent. Finally, mix the solution thoroughly to ensure uniform distribution. Remember to follow safety protocols when working with glutaraldehyde, as it is a hazardous chemical.

To make a 5mM solution of a compound, you would need to dissolve an appropriate amount of the compound in a solvent to reach a final concentration of 5 millimoles per liter (5mM). The exact amount of compound required will depend on its molecular weight and the volume of solvent you are using. You can use a molecular weight calculator to determine the amount needed to achieve a 5mM concentration.

Density can be calculated from molecular weight using the formula density = (molecular weight) / (molar volume). Molar volume is the volume occupied by one mole of the substance and can be calculated using the ideal gas law or experimental data. Dividing the molecular weight by the molar volume gives the density of the substance.

To calculate the volume of a compound when given its molecular weight and weight, you need to first convert the weight to moles using the molecular weight. Then, you can use the density of the compound to find the volume by dividing the weight in moles by the density. The formula is volume = weight (in moles) / density.

To prepare a 0.2 millimolar (mM) DPPH solution in ethanol, you need to dissolve 0.2 millimoles of DPPH in a final volume of 1 liter of ethanol. First, calculate the molecular weight of DPPH (usually around 394.33 g/mol) to determine the mass needed to dissolve in ethanol. Then add this mass of DPPH to ethanol and make up the volume to 1 liter.

To prepare 25 mM NH4HCO3, first calculate the amount of NH4HCO3 needed based on its molecular weight. Weigh out the calculated amount of NH4HCO3 and dissolve it in the appropriate volume of water to make a 25 mM solution. Finally, adjust the final volume with water if necessary.