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Dissolve 50 mg NaCl pro analysis in 1 L demineralized water, at 20 0C, in a volumetric flask.

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11y ago

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How do you prepare 50 ppm Na from Na-Cl?

Sodium is separated from sodium chloride by electrolysis.


How do you prepare TRIS-NaCl?

A water solution containing 50 mM tris(hydroxymethyl)aminomethane and 150 mM sodium chloride has a pH of 7,6.


How much percent is 50 ppm?

50 ppm is 0.005%


Is 100 ppm better or worse then 50 ppm?

100 ppm is worse than 50 ppm. The higher the ppm value, the more concentrated the substance is in the solution. In this case, a concentration of 100 ppm is twice as much as 50 ppm.


Calculate the mass of chlorine that can be formed from 50g of sodium chloride?

50 g sodium chloride (NaCl) contain 30,167 g chlorine.


How do you convert 0.5mM to ppm?

0.5Mm = 50 PPM


What is the percent by weight of NaCl in a saturated solution of sodium chloride at 50 degree Celsius?

The percent by weight of NaCl in a saturated solution at 50 degrees Celsius is approximately 26.3%. This means that in every 100 grams of the solution, 26.3 grams is NaCl.


How many grams of sodium chloride are required to prepare 500.0 mL of a 100 M solution?

In this instance, 50 mol of sodium chloride is needed and molar mass of NaCl is 58.5 g/mol. Hence the mass we need is 29250 g. But this amount of salt could not be dissolved in 500 ml of water, so we cannot prepare this solution practically.


What is the mass percent of sodium chloride in a solution prepared by adding 1 g of sodium chloride to 50 g of water?

The mass percent of sodium chloride can be calculated as follows: Mass of NaCl = 1 g Mass of water = 50 g Total mass of solution = 1 g + 50 g = 51 g Mass percent of NaCl = (Mass of NaCl / Total mass of solution) x 100% = (1 g / 51 g) x 100% ≈ 1.96%


What is the state of sodium chloride at 20 degrees?

Sodium Chloride is white crystalline solid at room temperature


How to prepare a 50liters of sea water solution of NaCl how much NaCl is required in gram?

The concentration of NaCl in sea water is about 35 g per kg. The density of seawater is about 1.025 kg/l, so you would need 50 * 1.025 kg sea water for 50 liters of solution.NaCl contributes to this with 35 * 1.025 * 50 g / kg * kg / l * l. consequently the result is about 1794 g of NaCl.


What volume of the 0.91 percent with NaCl is needed to prepare 100 ml of 0.45 percent with NaCl?

Your stock is a bit more than twice as concentrated as your target concentration. Take 49.45 ml of the stock and mix with enough water to bring it up to 100 ml. Now, the foregoing, notwithstanding, you want to prepare 100 ml...The precision of that measurement is going to drive your final results. It has only one significant digit so, your adding a quantity of stock with 4 significant digits (49.48 ml) is way too precise to be relevant. This is where you say, "I need to cut the concentration by about half so, I'll take 50 ml of the stock and add 50 ml of water. Sort of like how Justin Wilson measured ingredients for cooking.