Your stock is a bit more than twice as concentrated as your target concentration. Take 49.45 ml of the stock and mix with enough water to bring it up to 100 ml.
Now, the foregoing, notwithstanding, you want to prepare 100 ml...The precision of that measurement is going to drive your final results. It has only one significant digit so, your adding a quantity of stock with 4 significant digits (49.48 ml) is way too precise to be relevant. This is where you say, "I need to cut the concentration by about half so, I'll take 50 ml of the stock and add 50 ml of water. Sort of like how Justin Wilson measured ingredients for cooking.
Dissolve 30g of sodium chloride in 100 mL of water.
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
We first calculate the amount, in moles, of NaCl that we will need.Amount of NaCl needed = 0.24 x 400/100 = 0.096mol. Mass of NaCl needed = (23.0 + 35.5) x 0.096 = 5.616g So to produce 400ml of 0.24M NaCl solution, accurately add 5.616 grams of NaCl to 400ml of deionised water.
It depends on the final solution Volume you want to prepare. For 100ml of a 6M NaCL solution, you add 35.1g of NaCl to water until you reach 100ml. Dissolve and autoclave for 15 mins.
2.92%1g=1mL so;2.19/75 = 0.02920.0292*100%= 2.92% NaCl in a solution with total volume of 75 mL
The volume is 342 mL.
Dissolve 2g of NaCl in 100 cm3 water at normal temperature.
To prepare a 0.9% solution take 0.9grams NaCl and dilute with 100mls of water.
500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.
Dissolve 30g of sodium chloride in 100 mL of water.
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.
We first calculate the amount, in moles, of NaCl that we will need.Amount of NaCl needed = 0.24 x 400/100 = 0.096mol. Mass of NaCl needed = (23.0 + 35.5) x 0.096 = 5.616g So to produce 400ml of 0.24M NaCl solution, accurately add 5.616 grams of NaCl to 400ml of deionised water.
0.95% * 500 g = 4.75 g NaCl
The volume is 254,82 L.
It depends on the final solution Volume you want to prepare. For 100ml of a 6M NaCL solution, you add 35.1g of NaCl to water until you reach 100ml. Dissolve and autoclave for 15 mins.
If your solution is a total of 414g and 3.06% of it needs to be NaCl, then you just take 414 x .0306 = grams of NaCl. The rest of the grams will be from other species in the solution.