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http://www.sciencecompany.com/lab/test_solns.htm
Molartiy = moles of solute/Liters of solution200 mL X (1 Liter/10^2)= 0.200 Liters0.200 Liters x (0.05 M)= .01 moles of NaOH.01 moles of NaOH x (40 g NaOH/ 1 mole NaOH)= 0.4 g NaOH are required
10 g of NaCl in 2 kg of water is 5 g of NaCl in 1 kg of water.The molar mass of NaCl is 39,666 g.5 g is equal to 0,318 molal.
suspended in a solution with the following composition: 10% NaCl, 10% glucose and 40% albumin.
8.4 X 10^23/6.022 X 10^23 = 1.4 moles NaCl
Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed
You have to dilute the 10 mM NaCl 100X, 33,333X and 10X (X means "times") e.g. 100X: mix 10 ml of 10 mM Nacl with 990 ml of water (= 0,1 mM) 33,333X: mix 30 ml of 10 mM NaCl with 970 ml of water (= 0,3 mM) 10X: mix 100 ml of 10 mM NaCl with 900 ml of water (= 1 mM)
10 percent NaCl in distilled water is equivalent to 100 g/L NaCl.
Approximately 10 of them.
Mix 100 mL of a 1 N solution with 900 mL of distilled water.
That is approximately 10 cups.
If 10 is 10 molar for you, this is a saturated solution of NaCl.
% by weight in solution = = 100 * (weight solute) / [(weight solvent) + (weight solute)] = 100 * (weight solute) / [weight solution] = 100* 10 / [100 + 10] = 100 * 10 / 110 = 9.1%
A pen would weigh approximately 10 grams. 100 grams would be about 100 grams of feathers.
If you need to make just 100mL, then you need 1 tenth of a liter that is 5M. If you were to make 1L of 5 molar NaCl, you would need 5 times the molar mass of NaCl (58.44g/mol) dissolved in 1L of water. Thus for 1L of a 5M solution you need 5 * 58.44g, or 292.2 grams of NaCl. However, since we only want 100mL, which is 1/10 of a Liter, we also only need 1/10 the amount of NaCl, or 292.2 / 10, which is 29.22g. So, measure out 29.22g NaCl, and dissolve completly in a volume less than 100mL, say 80mL, then bring the final volume up to 100mL. You now have 100mL of a 5M NaCl solution.
100
That is approximately 1/10 of a litre
Yes, that is correct.