1ppm = 1mg/l
so, 1000ppm = 1gm/l or 0.1gm/100ml that is your required.
FW of NaCl = 58.5 (Na-23+Cl-35.5)
58.5gm NaCl = 23gm Na
Xgm NaCl = 0.1gm Na
therefor X = 0.2543gm
So dissolve 0.2543gm of NaCl to 100ml, to get 1000ppm of 100ml Na soln.
To make a 1000 ppm Na standard solution using NaCl, you would dissolve 0.0585 grams of NaCl (molecular weight of NaCl = 58.44 g/mol) in 1 liter of water. This would give you a solution with a concentration of 1000 ppm Na.
[348 (g NACl)] * [23 (g/mol Na)] * [1 (mol NaCl/mol Na)] / [58.5 (g/mol NaCl)] = [348*23/58.5] = 136.8 = 137 g Na
No, a 100 ppm NaCl solution means there are 100 parts per million of NaCl (sodium chloride) in the solution, not just sodium (Na) alone. To calculate the amount of sodium ions (Na+) in the solution, you would need to consider the molar mass of NaCl and the percentage of Na+ in NaCl.
In NaCl, the molar mass of Na is 22.99 g/mol and Cl is 35.45 g/mol. Therefore, the molar mass of NaCl is 58.44 g/mol. Given 8.0g of NaCl, the mass is distributed between Na and Cl in a 1:1 ratio. Thus, there are 3.5g of Na in 8.0g of NaCl.
The oxidation number of Na in NaCl is +1, while the oxidation number of Cl in NaCl is -1.
1 mg/l = 1ppm1 g/l = 1000 ppmNaCl ----------------> Na+ + Cl-58.5 g NaCl gives 22.989 g Na+(58.5 / 22.989) = 2.545 g of NaCl is required to give 1 g of Na+When 2.545 g of NaCl is dissolved in 1 liter water will yield 1000 ppm of Na+ in NaCl solution.
To make a 1000 ppm Na standard solution using NaCl, you would dissolve 0.0585 grams of NaCl (molecular weight of NaCl = 58.44 g/mol) in 1 liter of water. This would give you a solution with a concentration of 1000 ppm Na.
2.5 g of Nacl is to be dissolve in 100ml of water gives 10ppm of Na solution.
The cation, or positively charged ion, in NaCl is Na+.
The equation is: NaCl----------Na++ Cl-
NaCl---------------→Na+ + Cl-
Na+ + Cl- --> NaCl NaCl = salt.
NaCl --> Na+ + Cl- You could write water on either side I suppose, but it is negligible. I've also seen H2O written over the arrow.
[348 (g NACl)] * [23 (g/mol Na)] * [1 (mol NaCl/mol Na)] / [58.5 (g/mol NaCl)] = [348*23/58.5] = 136.8 = 137 g Na
Since NaCl is composed of one Na atom and one Cl atom, and the molar mass of Na is roughly 23 g/mol while that of Cl is about 35.5 g/mol, the molar mass of NaCl is approximately 58.5 g/mol. In 100 ppm NaCl, there are 100 mg of NaCl in 1 kg of solution. Therefore, the amount of Na in 100 ppm NaCl would be 100 mg * (23 g Na / 58.5 g NaCl) = ~ 39.3 ppm Na.
No, a 100 ppm NaCl solution means there are 100 parts per million of NaCl (sodium chloride) in the solution, not just sodium (Na) alone. To calculate the amount of sodium ions (Na+) in the solution, you would need to consider the molar mass of NaCl and the percentage of Na+ in NaCl.
In NaCl, the molar mass of Na is 22.99 g/mol and Cl is 35.45 g/mol. Therefore, the molar mass of NaCl is 58.44 g/mol. Given 8.0g of NaCl, the mass is distributed between Na and Cl in a 1:1 ratio. Thus, there are 3.5g of Na in 8.0g of NaCl.