Take 1000 ml volumetric flask weigh 2.542 g of Nacl
1ppm = 1mg/lso, 1000ppm = 1gm/l or 0.1gm/100ml that is your required.FW of NaCl = 58.5 (Na-23+Cl-35.5)58.5gm NaCl = 23gm NaXgm NaCl = 0.1gm Natherefor X = 0.2543gmSo dissolve 0.2543gm of NaCl to 100ml, to get 1000ppm of 100ml Na soln.
To prepare a 1000 ppm sodium solution from sodium chloride, first calculate the molecular weight of sodium chloride (NaCl). Then, dissolve the calculated amount of NaCl in a known volume of water to achieve a final concentration of 1000 ppm (1 mg/L). Make sure to accurately measure the mass of NaCl and volume of water to ensure the desired concentration is reached.
To make 1 liter of a 1000 ppm solution from a 1000 ppm stock solution, you would need 1 ml of the stock solution. This is because 1 ml of the 1000 ppm stock solution contains 1000 parts of solute in 1 million parts of solution, which is equivalent to 1 liter.
To make 1 liter of 0.4 M NaCl solution, you would need 200 mL of 2 M NaCl solution. This can be calculated using the formula Mi x Vi = Mf x Vf, where Mi is the initial molarity, Vi is the initial volume, Mf is the final molarity, and Vf is the final volume.
To prepare a 4.00 M NaCl solution, first calculate the moles of NaCl in 23.4 g. Then, determine the volume of water needed to make a total volume of 100.0 mL minus the volume of NaCl solution. Add the water to the NaCl to make a 100.0 mL solution.
1ppm = 1mg/lso, 1000ppm = 1gm/l or 0.1gm/100ml that is your required.FW of NaCl = 58.5 (Na-23+Cl-35.5)58.5gm NaCl = 23gm NaXgm NaCl = 0.1gm Natherefor X = 0.2543gmSo dissolve 0.2543gm of NaCl to 100ml, to get 1000ppm of 100ml Na soln.
We can use potassium chloride or better a mix NaCl + KCl.
take 1mg (0.001g) of mannitol and dilute it by deionised water to 100ml in 100ml measuring flask.The resulting solution is 10ppm.and then make further dilution to prepare required concentration.
To prepare a 1000 ppm sodium solution from sodium chloride, first calculate the molecular weight of sodium chloride (NaCl). Then, dissolve the calculated amount of NaCl in a known volume of water to achieve a final concentration of 1000 ppm (1 mg/L). Make sure to accurately measure the mass of NaCl and volume of water to ensure the desired concentration is reached.
Molar mass of NaCl =~58.4 g/mole0.1 N NaCl = 0.1 moles/liter To make 1 liter of 0.1N NaCl thus requires 0.1 moles/liter = 0.1 moles x 58.4 g/mole = 5.84 moles Dissolve 5.84 g (6 g using 1 sig. fig.) in a final volume of 1 liter to make 0.1N NaCl
We first calculate the amount, in moles, of NaCl that we will need.Amount of NaCl needed = 0.24 x 400/100 = 0.096mol. Mass of NaCl needed = (23.0 + 35.5) x 0.096 = 5.616g So to produce 400ml of 0.24M NaCl solution, accurately add 5.616 grams of NaCl to 400ml of deionised water.
Take the FW weight of the HgBr2-360.398g/moldivide it by the atomic weight of Mercury=200.59g/mol1g Hg in relation to FW of HgBr2 = 360.398/200.59 = 1.7966898gTo make 1000ppm of Hg, dissolve 1.79669g of HgBr2 in 1000ml of waterGet in touch if you are stuckIsaac Kiplagat
The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl
One way to find the density of NaCl is to dissolve a known mass of NaCl in a known volume of water to make a solution. Then, measure the volume of the solution and calculate the density using the formula: Density = mass of solution / volume of solution. Another way is to look up the density of a standard solution of known concentration.
You would need to dissolve 14.62 grams of NaCl in water to make a 0.5M NaCl solution with a final volume of 500 ml. This calculation is based on the formula: moles = Molarity x Volume (in liters), and then converting moles to grams using the molecular weight of NaCl.
The answer is 0,9 g pure, dried NaCl.
To make 1 liter of a 1000 ppm solution from a 1000 ppm stock solution, you would need 1 ml of the stock solution. This is because 1 ml of the 1000 ppm stock solution contains 1000 parts of solute in 1 million parts of solution, which is equivalent to 1 liter.