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What else can I help you with?
Why dont you weigh a solution dispensed at the beginning of an experiment?
Technically, as long as you record the volume of the solution and are sure of the concentration, you could extrapolate the weight.
How do you convert 100 gallons of 32 percent UAN to 28 percent UAN?
32% has a density of 11.04#/gal so 100 gal=1104#. 1104#*32%=353.28# of Nitrogen To convert 353.28# of Nitrogen into a 28% solution instead of 32% you must divide the #of nitrogen by the new solution value to get total pounds of new soultion and the ability to subtraced the two values to determine the total dilutant needed: 353.28#N in 28% solution would be 353.28/28%=1261.71# 28% solution 1261.71# 28% -1104# 32%= 157.71# of dilutant (water) needed to make 28% soultion. To figure out what percentace 32% is of the solution you divide the 32% solution weight by the new soultion weight: 1104/1261.71=.875 28% therefore is 87.5% of 32% by weight not volume. To solve the problem you need to divide the original weight of 32% by its percentage in the new solution to get the total solution weight of the new solution and then subtract the original solution weight to get the amount of dilutant needed to dilute 32% to a 28% solution. Do the following: (1104/.875)-1104=1261.71# of 28% solution. To dilulte 100 gal of 32% you will need to add water to get to the final weight of 28% solution 1261.71# 28%-1104# 32%=157.71# Dilutant (18.91 gal) Finished product you will have 118.91gal of 28% weighing 1261.71# 28% solution will be 10.611#/gal The fomula for this problem would be ((Galons 32% * 11.04)/.875)-(gal 32% * 11.04)= dilutant need. (gal 32% * 11.04)+ dilutant = # of 28% solution.
What is 6 to 8 percent of total body weight for an adult human?
do u really think i kno
How much does 1 body fat weigh?
Again, it is essential to know more then the question provides data on. Women need between 12 an 15 percent Essential body fat. Female athlletes carry about 18 percent bodyfat, healthy women carry about 26 percent, and an obese woman has 32 percent of more body fat. Men are considered obese at 25 percent Male athletes carry about 10 percent body fat and the survival level or Essential for men is at least two percent. When bodyfat falls below Essential levels the body's organs begin shutting down.
What is refers to the amount of blood in a body averaging 6 to 8 percent of total body weight for an adult human?
blood volume
What is the weight percent of a caffeine solution made by dissolving 8.35 g of caffeine C8H10N4O2 in 75 g of benzene C6H6?
The weight percent of a caffeine solution made by dissolving 8.35 g of caffeine in 75 g of benzene is calculated as: Weight percent = (mass of caffeine / total mass of solution) * 100 Weight percent = (8.35 g / (8.35 g + 75 g)) * 100 Weight percent ≈ 10.0%
What is the answer of what is the weight percent of potassium nitrate in a solution that is made by dissolving 30.0 g of potassium nitrate in 90.0 g of water?
To find the weight percent of potassium nitrate in the solution, first calculate the total mass of the solution, which is the sum of the mass of potassium nitrate and the mass of water: 30.0 g + 90.0 g = 120.0 g. Next, use the formula for weight percent: (mass of solute / total mass of solution) × 100%. Thus, the weight percent of potassium nitrate is (30.0 g / 120.0 g) × 100% = 25.0%.
How much water must be added to 40 ml of a 25 percent by weight solution to make a 2 percent by weight solution?
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
How much water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution?
To make a 2% solution from a 25% solution, you need to dilute it. Let x ml be the amount of water needed. Using the equation for mass balance: 0.25(40) = 0.02(40 + x), solve for x to find that x = 875 ml of water needs to be added.
What is the weight of 10 percent acetic acid?
The weight of 10 percent acetic acid solution would depend on the total volume of the solution. For example, if you have 100 grams of a 10 percent acetic acid solution, it would contain 10 grams of acetic acid.
How many grams in 1 percent solution?
A 1% solution normally contains 1 gram of active ingredient per 100 ml of solution (weight-volume percent) Could also be 1gm per 100 gms (weight-weight percent)- but normally weight-volume is used.
How do make a percent sucrose solution?
To make a percent sucrose solution, dissolve a specific weight of sucrose in a specific volume of water. For example, to make a 10% sucrose solution, dissolve 10 grams of sucrose in 90 mL of water. The formula to calculate the amount of sucrose needed is: (percent sucrose/100) x volume of solution = weight of sucrose (in grams).
How do you determine the number of grams of an active ingredient in a solution based on the percent strength?
You can determine the number of grams of an active ingredient in a solution by multiplying the percent strength of the solution by the total weight or volume of the solution. This will give you the weight of the active ingredient present in the solution.
What is the percent by weight of NaCl in a saturated solution of sodium chloride at 50 degree Celsius?
The percent by weight of NaCl in a saturated solution at 50 degrees Celsius is approximately 26.3%. This means that in every 100 grams of the solution, 26.3 grams is NaCl.
What is another way to express the concentration of a glucose solution that is 0.01 percent by weight?
Another way to express the concentration of a 0.01 percent by weight glucose solution is to say it is a 100 parts per million (ppm) solution. This means there are 100 grams of glucose in every 1 million grams of solution.
What is the another way to express the concentration of a glucose solution that is 0.01 percent by weight?
Another way to express the concentration of a glucose solution that is 0.01 percent by weight is as 100 parts per million (ppm). This means there are 100 grams of glucose in 1 million grams of solution.
What is the percent of the solution if the solute is 5grams and the solvent is 50grams?
weight %=weight of solute/weight of solute+weight of solvent. =5/5+50 =5/55=0.91%
