else
printf("NOT TEN");
a = 100;
}
The above code looks perfectly normal. If a is 10, then print "TEN" otherwise print "NOT TEN" and set a to 100.
With certain languages (C/C++ and Java included), that code would not quite work as described. The way the code is indented can make someone believe that it is doing something else.
According to the way C/C++ and Java would interpret the above code, it should look more like this:
void doStuff(int a) {
if(a == 10) {
printf("TEN");
}else {
printf("NOT TEN");
}
a = 100;
}
Which means that no matter what, a would be set to 100 at the end of the function call, which is not how the indentation made it look in the original example.
Keep in mind that both examples are identical in function if interpreted by a C/C++ or Java style compiler.
It can be either
if (cond1) { if (cond2) stmt1; else stmt2; }
or
if (cond1) { if (cond2) stmt1; } else stmt2;
It is important to rembember that the compiler does not know which of those you meant, so it choose the first interpretation: the dangling else belongs to the inner if.
If you always use braces to explicitly define the scope of the if and the esle statement then the code becomes clearer to other programmers.
if (something) {
do_something;
} else {
do_something_else;
}
done;
Java and C/C++ allow short form constructs such as
if (something)
do_something;
else
do_someing_else;
but this is not always clear as in
if (something)
do_something;
else
do_something_else;
done;
Using a style checking tool like PMD allows developers to double check their code for these types of problems.
The ambiguity that arises in a nested if statement due to more number of if then the number of else clauses is also as dangling else problem. a confusion is created with which if does the additional else clause match up.
Nothing, but be careful with the dangling else's: if (cond1) if (cond2) stmt1; else stmt2; means: if (cond1) { if (cond2) stmt1; else stmt2; } not this: if (cond1) { if (cond2) stmt1; } else stmt2;
Here is an example:if (exp1) if (exp2) stmt1 else stmt2It could mean different things, like:if (exp1) { if (exp2) stmt1 else stmt2 }if (exp1) { if (exp2) stmt1 } else stmt2;if (exp1) { if (exp2) stmt1 else stmt2 } else stmt2Well, the first is the good answer, but it can be confusing, so when in doubt use {brackets}
This could lead to a memory leak
The pointer that points to a block of memory that does not exist is called a dazzling pointer or wild pointer
There is nothing that we can do or build that can prevent tornadoes.
The dangling else problem occurs when an if-else construct is ambiguous, and it is unclear which if statement should be associated with the else statement. This can lead to unintended behavior in the code if not handled properly. It is recommended to use braces to explicitly define the scope of if-else blocks to avoid this issue.
it's a uvula
The climber was left dangling for his life on the edge of the cliff.She did not like the way the bracelet was dangling when she drove.Somehow, there is a sock dangling from the tree.
Nothing, but be careful with the dangling else's: if (cond1) if (cond2) stmt1; else stmt2; means: if (cond1) { if (cond2) stmt1; else stmt2; } not this: if (cond1) { if (cond2) stmt1; } else stmt2;
The antonym of "dangling" could be "secure" or "fixed."
The antonym for dangle is dangling
The man was dangling from the bridge for his life
Dangling Man was created in 1944.
dangling gerund is a form of verb that act as noun......
Dangling refers to a situation where a pointer in a computer program points to a memory location that has been deallocated or is no longer valid. This can lead to unpredictable behavior and crashes in a program. Dangling pointers are a common source of bugs in C and C++ programs.
There is A dangling sentence
Dangling earlobe is dominant.