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Are algebraic expressions needed in an equation?
Yes normally because the LHS expression equals the RHS expression
What is the value of an equation that makes the equation a true statement?
The LHS expression = RHS expression
Is there three sides to an equation?
Not normally because its LHS is equal to its RHS
An equation always have two sides namely LHS and RHS it is true?
Yes
In mathematics a is a sentence that contains an equal sign?
an equation it signifies something on LHS is equal to RHS
9 plus 3 equals 722 5 plus 7 equals 536 6 plus 8 equals 847 7 plus 2 equals what ans will come?
Answer is 411 Logic: You multiply the two numbers in LHS of the equation and reverse the result to form the first two digits of RHS and for the 3rd digit you subtract one from the 2nd number on the LHS of the equation.
What is some advice for solving systems of equations?
Always keep the equation in balance inasmuch that what is done on the RHS must be done on the LHS of the equation.
From the equation X-Y equals 2 what is Y when X equals 3?
X - Y = 2 When X = 3 you have 3 - Y = 2 Moving Y to RHS: 3 = Y + 2 Moving 2 to LHS: 1 = Y
What is algebraic or numerical sentence that shows the two quantites are equal?
It is an equation that shows that the LHS is equal to the RHS by means of an equality sign which is =
What would you need to help you with it comes to solving equations?
When solving equations remember that whatever operations are performed on the LHS of the equation must be performed on its RHS to keep the equation in balance.
How you solve the problems about mathematical induction?
first find p(1) n prove dat its lhs n rhs r the same then go the assumption ie,P(k) then asume it to be true n assume it to be true with P(k=1) ,at last dependin on your problem prove that lhs=rhs{tip: dont loose ur hope cuz it distroys evrithin} ;)
Can you Show 1 over sinx cosx - cosx over sinx equals tanx?
From the Pythagorean identity, sin2x = 1-cos2x. LHS = 1/(sinx cosx) - cosx/sinx LHS = 1/(sinx cosx) - (cosx/sinx)(cosx/cosx) LHS = 1/(sinx cosx) - cos2x/(sinx cosx) LHS = (1- cos2x)/(sinx cosx) LHS = sin2x /(sinx cosx) [from Pythagorean identity] LHS = sin2x /(sinx cosx) LHS = sinx/cosx LHS = tanx [by definition] RHS = tanx LHS = RHS and so the identity is proven. Q.E.D.
