Titties
When a copper rod is on fire, it will oxidize and produce copper oxide. The flames from the fire will be green or bluish-green due to the presence of copper ions. Eventually, the rod will likely melt if the fire is hot enough.
Sugar donates electrons that reduce blue copper (II) sulfate to orange copper (I) oxide.
Copper (I) Oxide or Cuprous Oxide
Cuprous oxide or copper(I) oxide. This is copper in oxidation state '1'.
CuO = Cupric Oxide Cupric = Cu2+ and is not Cu The correct answer would be CuO = Copper Monoxide Copper (II) oxide is the name of the compound CuO.
because copper is located below hydrogen in reactivity series, thus hydrogen can reduce copper oxide which mean it undergo reduction reaction (loss of oxygen) CuO + H2 → Cu + H2O while, hydogen can't reduce magnesium because magnesium is located higher than hydrogen in reactvity series. it must be added with oxygen which mean it undergo oxidation reaction (gain oxygen) 2Mg + O2 → 2MgO i hope this will help u a lot ^_^
To extract copper from copper nitrate, you can heat the copper nitrate in a crucible to decompose it into copper oxide, releasing nitrogen dioxide gas. Then, reduce the copper oxide to copper metal by heating it with carbon in a reducing atmosphere, such as hydrogen or carbon monoxide. The copper metal will be left behind as a residue in the crucible, which can then be collected and purified.
The correct chemical formula for copper oxide is Cu2O for copper(I) oxide (cuprous oxide) and CuO for copper(II) oxide (cupric oxide).
When copper is burned in the presence of air, it forms copper oxide. Copper oxide can exist in different forms, such as copper(I) oxide (Cu2O) or copper(II) oxide (CuO), depending on the conditions of the reaction.
Magnesium + copper oxide --> magnesium oxide + copper
copper oxide
copper oxide---> copper + oxygen