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The chlorate ion is ClO3-. Some text books say that the oxidation number of the whole ion is equal to the charge, so in this cas it would be -1. However most teachers would sya that oxidation numbers only refer to atoms. So working out the oxidation numbers:-

oxygen is -2, (using the rule, or if you use the he electronegativity method- gives the same answer as O is more electronegatoive than Cl)

the sum of oxidation numbers of Cl and O are -1 (the charge on the ion) - I'll call the oxidation number of Cl OxCl

-1 =OxCl + (3* -2)= OxCl -6

therefore OxCl = +5

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Q: How do you solve for the oxidation number of a chlorate ion?
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