Is it y=18-2x?
If so,
when solving x-intercept, y=0
y=18-2x
18-2x=y
18-2x=0
-2x=-18
-2x/-2=-18/-2
x=9
so, x intercept is 9
when solving y-intercept, x=0
y=18-2x
18-2x=y
18-2(0)=y
y=-12
so, y intercept is -12
In the equation y = f(x), Put x = 0 and solve for y. Those are the y intercepts. Put y = 0 and solve for x. Those are the x intercepts.
I believe that you need an equation to solve for the x and y intercepts.
The x coordinate for all y intercepts is 0, just as the y coordinate for all x intercepts is 0.
Factoring a quadratic allows you to solve the x and y intercepts. The x-intercepts in the factored form are the inverse of the constants. The y-intercept is the product of the x-intercepts multipied together. Example: x²-10x-24 = (x+2)(x-12) +2 and -12 are the constants. So ur x-intercepts are (-2,0) (12,0). The y intercept is -24 because -2 X 12 = -24.
To solve for intercepts on a straight line graph put the equation in the form y=mx+c where c is the y-intercept and you have the y intercept. Now to solve x-intercept set y=0 eg y=2x+5 0=2x+5 2x=-5 x=-2.5 For intercepts on other forms of graphs eg parabola y-intercept= make x equal to 0 and solve x-intercept= make y equal to 0 and solve
The x and y intercepts are where a line on a graph intersects (crosses over) the x or y axis.
18
To find the y-intercept you substitute in 0 for x and solve. To find the x- intercept you substitute in 0 for y and solve. If you do it correctly you should find the x-intercept to be -3 and the y-intercept to be 3.
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
the x is dependent and the y is independent and the x numbers cant repeat themself and yes they do have intercepts
-- Take the equation. -- Say to yourself, "At the x-intercept, y=0". Set 'y' equal to zero, solve the equation for 'x', and you have the x-intercept. -- Take the original equation again. -- Say to yourself, "At the y-intercept, x=0". Set 'x' equal to zero, solve the equation for 'y', and you have the y-intercept.
The quadratic (parabola) intercepts the x-axis when y = 0. So substitute y=0 into y = f(x). Then you can solve for the x-values by any number of ways: Factoring, completing the square, or Quadratic Formula. It may turn out that the values of x which satisfies y=0 are complex {have an imaginary component}, which will tell you that the parabola does not have an x-intercept.